Answer:

General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
- Standard Form: ax² + bx + c = 0
- Quadratic Formula:

<u>Algebra II</u>
- Imaginary Numbers: √-1 = i
Step-by-step explanation:
<u>Step 1: Define Equation</u>
x² + 20 = 0
<u>Step 2: Identify Variables</u>
a = 1
b = 0
c = 20
<u>Step 3: Find roots </u><em><u>x</u></em>
- Substitute:

- Exponents:

- Multiply:

- Subtract:

- Factor:

- Simplify:

- Divide:

It doesn't give any answers? I think the first one is 14 the second one is -4 and the third one is 10
Answer:
38.28cm^2
Step-by-step explanation:
Area of rectangle = 24cm^2
Area of rectangle = 8cm^2
Area of semicircle = 6.28cm^2
Since this is an improper fraction, you simplify it into a mixed number.
4 goes into 6 1 time. 2 left left over, resulting in 1 2/4. Simplify that into
1 1/2

↝ Form into
where a > 0 (Optional)
↝ Multiply -1 for both sides.
↝ Then proceed with the Quadratic Formula.
x = [-b ± (√b²-4ac)]/2a ↝ Quadratic Formula

↝ As you can see that inside the square root, the numbers cannot be negative. Therefore, the solutions are imaginary.
↝ Solution with Real Numbers System ↝ There are no real solutions.
↝ Solution with Complex Number System ↝

Therefore, the answer for Complex Number System is (5±√7i)/2