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lawyer [7]
3 years ago
6

When is the bond between the actin and myosin head is broken? when an ATP molecule binds to the myosin head when an ATP molecule

binds to the actin molecule when an ATP molecule breaks down on the myosin head when an ATP molecule breaks down on the actin molecule when ADP and phosphate bind to the myosin head
Computers and Technology
1 answer:
Goshia [24]3 years ago
8 0

Answer:

The answer is when an ATP molecule binds to the myosin head.

Explanation:

when an ATP molecule binds to the myosin head. The molecule basis for this interaction is the binding of myosin to actin filaments, allowing the binding ATP dissociates myosin from actin.

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someone please do this for and send a screeshot or picture please its really important for my examsss :D​
dusya [7]

Answer:

I  dont know

Explanation:

i dont know

4 0
2 years ago
Initialize the list short_names with strings 'Gus', 'Bob', and 'Zoe'. Sample output for the given program:
ohaa [14]

Answer:

Following are the correct code to this question:

short_names=['Gus','Bob','Zoe']#defining a list short_names that holds string value

print (short_names[0])#print list first element value

print (short_names[1])#print list second element value

print (short_names[2])#print list third element value

Output:

Gus

Bob

Zoe

Explanation:

  • In the above python program code, a list "short_names" list is declared, that holds three variable that is "Gus, Bob, and Zoe".
  • In the next step, the print method is used that prints list element value.
  • In this program, we use the list, which is similar to an array, and both elements index value starting from the 0, that's why in this code we print "0,1, and 2" element value.
7 0
2 years ago
Beth wants to add information to her PowerPoint presentation that is hidden from her audience and only she will
Veseljchak [2.6K]

Answer:

howdy

Explanation:

4 0
3 years ago
Given a variable s that is associated with the empty string, write some statements that use a while loop to associate s with a s
ArbitrLikvidat [17]

Answer:

Following are the program in the Python Programming Language.

#declare empty string variable

s=""

#declare variable that store "*" as string

x= "*"

#set the while loop

while(len(s) < 777):

   #initialize the value of 'x' in 's'

   s= x

   x += "*"

Explanation:

<u>Following are the description of the program</u>.

  • Set an empty variable to store the string type values.
  • Again, set a variable 'x' and initialize asterisks in it as a string.
  • Set the while loop that iterate, when the length of the variable 's' is less than 777, then initialize the value of the variable 'x' in the variable 's' and concatenate asterisks with the variable 's'.
8 0
3 years ago
This the code from the last post I did
Andrew [12]

import java.util.Scanner;

public class JavaApplication86 {

   

   public static void main(String[] args) {

       Scanner scan = new Scanner(System.in);

       int x = 0, c = 0, sum = 0;

       while (true){

           x = scan.nextInt();

           System.out.println("You entered: "+x);

           if (x == -1){

               break;

           }

           sum += x;

           c++;

       }

       System.out.println("The sum is "+sum);

       System.out.println("You entered "+c +" numbers");

   }

   

}

This works for me. Instead of subtracting one from c and adding one to sum, I used an if statement to break away from the while loop if the entered number is -1.

3 0
2 years ago
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