Part A: solve -mk - 120 > 95 for m. Show your work.

3-1/3n< 6;n>-9 What is n???

r-ruslan [8.4K]

Answer:

i don't understand your question, but i'll try to the best of my ability.

the answer to that is:

-8.33333333333

Step-by-step explanation:

let me break this down into a way you might understand.

1: 3-1=2

2: 2 divided by 3=0.66666666666.

3: i don't know if the "< 6;n>", was meant to be in the equation, so i just added the rest of it up.

if that's not right let me know. i'm pretty clueless sometimes, and this might just be a higher level of math that i don't know.

you're welcome though, (i suppose..) and have a great day.

6 0

3 years ago

2+2=___<br><br> Y'all are working hard, so here are some points to whoever ends up answering first!

fgiga [73]

Answer:

4 plzjfhrvrhgegrg iejve iwhcrv

8 0

3 years ago

Read 2 more answers

Which of these is not a possible r-value?

Tems11 [23]

Answer:

Step-by-step explanation:

A

4 0

4 years ago

A fried chicken franchise finds that the demand equation for its new roast chicken product, "Roasted Rooster," is given by p = 4

LUCKY_DIMON [66]

Answer:

1. $q=(\dfrac{45}{p})^{\frac{2}{3}}$

2. $E_d=-\dfrac{2}{3}$

Step-by-step explanation:

The given demand equation is

$p=\dfrac{45}{q^{1.5}}$

where p is the price (in dollars) per quarter-chicken serving and q is the number of quarter-chicken servings that can be sold per hour at this price.

Part 1 :

We need to Express q as a function of p.

The given equation can be rewritten as

$q^{1.5}=\dfrac{45}{p}$

Using the properties of exponent, we get

$q=(\dfrac{45}{p})^{\frac{1}{1.5}}$ $[\because x^n=a\Rightarrow x=a^{\frac{1}{n}}]$

$q=(\dfrac{45}{p})^{\frac{2}{3}}$

Therefore, the required equation is $q=(\dfrac{45}{p})^{\frac{2}{3}}$ .

Part 2 :

$q=(45)^{\frac{2}{3}}p^{-\frac{2}{3}}$

Differentiate q with respect to p.

$\dfrac{dq}{dp}=(45)^{\frac{2}{3}}(-\dfrac{2}{3})(p^{-\frac{2}{3}-1}})$

$\dfrac{dq}{dp}=(45)^{\frac{2}{3}}(-\dfrac{2}{3})(p^{-\frac{5}{3}})$

$\dfrac{dq}{dp}=(45)^{\frac{2}{3}}(-\dfrac{2}{3})(\dfrac{1}{p^{\frac{5}{3}}})$

Formula for price elasticity of demand is

$E_d=\dfrac{dq}{dp}\times \dfrac{p}{q}$

$E_d=(45)^{\frac{2}{3}}(-\dfrac{2}{3})(\dfrac{1}{p^{\frac{5}{3}}})\times \dfrac{p}{(45)^{\frac{2}{3}}p^{-\frac{2}{3}}}$

Cancel out common factors.

$E_d=(-\dfrac{2}{3})(\dfrac{1}{p^{\frac{5}{3}}})\times \dfrac{p}{p^{-\frac{2}{3}}}$

Using the properties of exponents we get

$E_d=-\dfrac{2}{3}(p^{-\frac{5}{3}+1-(-\frac{2}{3})})$

$E_d=-\dfrac{2}{3}(p^{0})$

$E_d=-\dfrac{2}{3}$

Therefore, the price elasticity of demand is -2/3.

3 0

3 years ago

In 2017 the state University’s men’s basketball team finished the season ranked 34 out

Alex Ar [27]

Answer:

sorry I don't know the answer

8 0

3 years ago