Part A: solve -mk - 120 > 95 for m. Show your work.
1 answer:
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Answer:
(a) 2 miles
(b) 2 miles
Step-by-step explanation:
Let the distance of the satellite from Station A = |AC|
Let the height of the Satellite from the ground = |DC|
(a) Using size rule on triangle ABC, we can find the value of AC with the following relationship:
|AC|/ Sin 84.2 = 10/ Sin 8.8
|AC| = 10 x (Sin 84.2/Sin 8.8)
= 10 x 0.1529
=1.529 miles
= 2 miles (to the nearest mile)
(b) To calculate the |DC|, we apply the relationship of right-angle triangle ADC:
Sin 87 = |DC|/ 1.529
|DC| = 1.529 Sin 87
= 1.526 miles
= 2 miles (to the nearest mile)
