To solve this problem we need to use the induced voltage ratio law with respect to the number of turns in a solenoid. So
For the given values we have to
Replacing we have that,
Therefore the RMS value for secondary is 30V.
The current can be calculated at the same way, but here are inversely proportional then,
Replacing we have
Therefore the rms value of current for secondary is 40mA
If it didn’t have energy then we wouldn’t be able to move very much and machines will be slower
Start with basic concept that you have the same amount of watts it's just how far away you are dictates the watts/meter squared (per area). As the distance from the object is increased, the area increases as distance squared (think of a sphere of increasing radius, as you increase the radius, the surface area increases as r^2, double radius, you get 4 times area, triple radius, 9 times area, and so forth). so safe from acoustical effects (reflections off walls, etc) as you increase the distance from a speaker, the sound will decrease by a factor of the distance squared, as before 2x distance =1/4 power, 3x distance =1/9 power.
<span>so the only thing left out of your questions is what distance from speaker is the level at 10^-6 W/m^2 and what distance is point B from the speaker, and apply the 1/distance^2 principle. </span>
<span>The power at point B (PB) is the following: </span>
<span>power at given power level (we will call this point A or PA). </span>
<span>PB=PA*(DA/DB)^2 </span>
<span>Where PB is power level at PB (in W/m^2) </span>
<span>PA=power at point A or 10^-6 W/m^2 </span>
<span>DA=distance from speaker to point A </span>
<span>DB=distance from speaker to point B. </span>
<span>Object B stays neutral but becomes polarized.
Hope this helps.
~Jurgen</span>