During fuel burn, the vertically launched Terrier-Sandhawk rocket had an acceleration of 300m/s^2 ( about 30 times free-fall acc
1 answer:
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Answer:
A) first laser
B) 0.08m
C) 0.64m
Explanation:
To find the position of the maximum you use the following formula:
m: order of the maximum
λ: wavelength
D: distance to the screen = 4.80m
d: distance between slits
A) for the first laser you use:
for the second laser:
hence, the first maximum of the first laser is closer to the central maximum.
B) The difference between the first maximum:
hence, the distance between the first maximum is 0.08m
C) you calculate the second maximum of laser 1:
and for the third minimum of laser 2:
Finally, you take the difference:
hence, the distance is 0.64m