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solong [7]
3 years ago
9

During fuel burn, the vertically launched Terrier-Sandhawk rocket had an acceleration of 300m/s^2 ( about 30 times free-fall acc

eleration called 30g). The fuel burned for 8.0 s. Find the height of the Terrier-Sandhawk rocket at the end of fuel burn.
Physics
1 answer:
sertanlavr [38]3 years ago
3 0
Initial launch velocity, u = 0
Acceleration, a = 300 m/s²
Duration, t = 8.0 s

The distance traveled is
h = ut + (1/2)*a*t²
   = (0 m/s)*(8 s) + 0.5*(300 m/s²)*(8 s)²
   =  9600 m

Answer: 9600 m
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1/(0.60 - r)² = 3 /r²

r = 0.38 m

r = 38 cm


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