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2 years ago

Which type of stress is a uniform stress that doesn't lead to earthquakes?

Physics

2 answers:

Mice21 [21]2 years ago

6 0

Answer:

Lithostatic pressure

Explanation: when you search up what lithostatic means you will see.

ElenaW [278]2 years ago

4 0

Answer:

C) Lithostatic pressure

Explanation:

An earthquake is what happens when two blocks of the earth suddenly slip past one another. The surface where they slip is called the fault or fault plane.

In the Earth the pressure due to the weight of overlying rocks is a uniform stress and is referred to as confiningstress. If stress is not equal from all directions then the stress is a differential stress. Three kinds of differential stress occur. Shear stress, which result in slippage and translation.

You might be interested in

What is the primary force that causes the seafloor to spread and continents to drift?

jekas [21]

The primary force would be Thermal Convection, it pushes it and thus makes continents drift.
-Hope that helps, Nexxmexx :3

5 0

3 years ago

The stopping sight distance for a car traveling at 50 mph is 461 ft (including both perception-reaction distance and braking dis

Ivan

Answer:

2.08 s

Explanation:

We are given that

Speed,v=50mph=73.3ft/s

1 mile=5280 feet

1 hour=3600 s

Distance,d=461 ft

t=2.5 s

v'=60 mph=88 ft/s

We have to find the perception reaction time.

Perception reaction distance= $d_p=vt=73.3\ti es 2.5=183.25 feet$

$d_p=d'_p$

$d'_p=v't$

$t'=\frac{183.25}{88}=2.08 s$

4 0

3 years ago

Un automovil parte del reposo y acelera uniformemente hasta alcanzar una rapidez de 0,255km/h en un tiempo de 3/4 Minutos determ

Elden [556K]

Answer:

a = 1.5*10^-3 m/s^2

x = 0.033m = 3.3cm

Explanation:

To calculate the acceleration and the distance traveled by the car you use the following formulas:

$v=v_o+at$ (1)

$x=v_ot+\frac{1}{2}at^2$ (2)

v: final velocity = 0,255 km/h

vo: initial velocity = 0 m/s

t: time = 3/4 min

a: acceleration = ?

x: distance

In order to use the equations (1) and (2) you first convert the units of the final velocity to m/s, and the time to seconds.

$v=0,255\frac{km}{h}*\frac{1000m}{1km}*\frac{1h}{3600s}\\\\v=0.07m/s\\\\t=\frac{3}{4}min*\frac{60s}{1min}=45s$

Next, you solve the equation (1) for the acceleration a:

$a=\frac{v}{t}=\frac{0.07m/s}{45s}=1.5*10^{-3}\frac{m}{s^2}$

With this value of a you can calculate the distance traveled by the car, by using the equation (2):

$x=\frac{1}{2}(1.5*10^{-3}m/s^2)(45s)^2=0.033m=3.3cm$

hence, the acceleration of the car is 1.5*10^-3 m/s^2 and the distance traveled in 3/4 min is 0.033m

5 0

3 years ago

How is the acceleration of falling objects affected by gravity

Oliga [24]

Gravity is the CAUSE of 'falling', and the cause of acceleration
while falling.

Objects falling near the Earth's surface all have the same acceleration ...
about 9.8 m/s².

4 0

3 years ago

Matt and Anna Killian are frequent fliers on Fast-n-Go Airlines. They often fly between two cities that are a distance of 1575

marin [14]

Answer:

Speed of wind = 50mi/hr, Speed of plane in still air = 400mi/hr

Explanation:

Let the speed of the wind = Vw,

Speed of the plane in still air = Vsa,

The first trip the average speed of the plane = 1575mi/4.5hours = 350mi/hr

The coming trip the wind behind = 1575mi/3.5hrs = 450

Write the motion in equation form

First trip ( the plane flew into the wind)

Vaverage = Vsa - Vw

350 = Vsa - Vw

Second trip the wind was behind

450 = Vsa +Vw

Adding the two equation

800 = 2Vas

Vas = 800/2 = 400mi/hr

Substitute for Vas into equation 1

350mi/hr = 400mi/hr - Vw

Vw = 400-350 = 50mi/hr

6 0

3 years ago