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alexandr1967 [171]
3 years ago
5

In an electroplating process, copper (ionic charge +2e, atomic weight 63.6 g/mol) is deposited using a current of 10.0 A. What m

ass of copper is deposited in 10.0 minutes? Avogadro's number is 6.022 × 1023 molecules/mol and e = 1.60 × 10-19 C.
Physics
1 answer:
statuscvo [17]3 years ago
5 0

Answer:

1.974 g

Explanation:

Electrochemical equivalent of copper, z = 0.000329 g/C

I = 10 A

t = 10 minutes = 10 x 60 = 600 seconds

By the use of Farady's law of electrolysis

m = z I t

m = 0.000329 x 10 x 600

m = 1.974 g

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Explanation:

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A person throws a ball straight up in the air. The ball rises to a maximum height and then falls back down so that the person ca
Lana71 [14]

Answer:

The acceleration is about 9.8 m/s2 (down) when the ball is falling.

Explanation:

The ball at maximum height has velocity zero

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.8 m/s² (positive downward and negative upward)

v=u+at\\\Rightarrow 0=u-9.8\times t\\\Rightarrow u=9.8t

The accleration 9.8 m/s² will always be acting on the body in opposite direction when the body is going up and in the same direction when the body is going down. The acceleration on the body will never be zero

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4 years ago
The total yearly world consumption of energy is approximately 4.0 × 1020 J. How much mass would have to be completely converted
BabaBlast [244]

Answer:

m = 4.4 × 10³ kg

Explanation:

Given that:

The total yearly energy is 4.0 × 10²⁰ J

The amount of mass that provides this energy can be determined by using the formula:

E = mc²

where;

c = speed of light in free space = (3 × 10⁸)

4.0 × 10²⁰ = m × (3 × 10⁸)²

m = \dfrac{4.0 \times 10^{20} }{(3\times 10^8)^2}

m = 4.4 × 10³ kg

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3 years ago
A hockey ball accelerates from 0.m/s to 25m/s in 0.05 seconds what is the acceleration of the ball ?
S_A_V [24]

Answer:

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25/0.05 .

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3 years ago
A heavy anvil is suspended by a 0.75 m long steel wire that has a mass of 12 g. When the wire is plucked, it hums at its fundame
Dima020 [189]

Explanation:

It is given that,

length of steel wire, l = 0.75 m

Mass of the wire, m = 12 g = 0.012 kg

Fundamental frequency, f = 120 Hz

We need to find the mass of the anvil (m'). The fundamental frequency is given by :

f=\dfrac{v}{2l}

v is the speed of the mass

Speed is given by :

v=\sqrt{\dfrac{T}{\mu}}

\mu is the mass per unit length,\mu=\dfrac{m}{l}

f=\dfrac{1}{2l}\sqrt{\dfrac{T}{\mu}}

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f=\dfrac{1}{2l}\sqrt{\dfrac{Tl}{m}}

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m'=\dfrac{T}{g}

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So, the mass of the anvil is 52.89 kg. Hence, this is the required solution.

6 0
4 years ago
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