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dolphi86 [110]
3 years ago
15

Work is being done in which of these situations? All motions are at a constant velocity (including velocity = zero).

Physics
2 answers:
Black_prince [1.1K]3 years ago
4 0
Work is done only when there is a displacement of the object on which a force is applied in the direction of the force.
ale4655 [162]3 years ago
4 0

Answer:

Work is done only when there is a displacement of the object on which a force is applied in the direction of the force.

Explanation:

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What do you think happens to the temperature when water changes to gas?
Olenka [21]

Answer:

it gets hot and more hot until it turns to gas

Explanation:

5 0
3 years ago
How long will the ball be in the air if the cliff is 120 m tall and the ball falls to the base of the cliff?
Readme [11.4K]

Answer:

Explanation:

4.95s≈5s

Use equation :

h=G*t²/2

h=120m ----hight of cliff

G=9.81m/s²

t=?

-----------------------

h=G*t²/2

120m=9.81m/s²*t²/2

240m=9.81m/s²*t²

t²=240m/ 9.81m/s²

t²=24.46s

t=√24.46s²

t=4.95 s≈5s

3 0
3 years ago
The section of the electromagnetic spectrum that humans can generally see is called _____ light.
Lisa [10]

Answer:

(A) Visible

Explanation:

  • The section of the electromagnetic spectrum that humans can generally see is called visible light.

White light is visible light and the range of visible wavelengths ranges from 400 - 700 nanometers.

8 0
3 years ago
Read 2 more answers
A cart of mass 6.0 kg moves with a speed of 3.0 m/s towards a second stationary cart with a mass of 3.0 kg. The carts move on a
IgorLugansk [536]

Answer:1.5

Explanation:

Given

mass of first  cart m_1=6 kg

initial Velocity u_1=3 m/s

mass of second cart m_2=3 kg

u_2=0 m/s

In the absence of External Force we can conserve momentum

m_1u_1+m_2u_2=(m_1+m_2)v

v=\frac{m_1u_1+m_2u_2}{m_1+m_2}

v=\frac{6\times 3+3\times 0}{6+3}

v=2 m/s

Final kinetic Energy of two masses

K.E._2=\frac{1}{2}(m_1+m_2)v^2

K.E._2=\frac{1}{2}\cdot (3+6)\cdot (2)^2

K.E._2=18 J

Initial Kinetic Energy

K.E._1=\frac{1}{2}m_1u_1^2+\frac{1}{2}m_2u_2^2

K.E._1=\frac{1}{2}6\times 3^2+0

K.E._1=27 J

ratio =\frac{K.E._1}{K.E._2}=\frac{27}{18}=1.5

5 0
3 years ago
A force of 8,480 N is applied to a cart to accelerate it at a rate of 26.5 m/s2. What is the mass of the cart?
katrin2010 [14]

Answer:

<h2>320</h2>

Just use F =ma where m is mass and a is acc.

8 0
3 years ago
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