They are 1st one is vertical angles, second one is complementary
the data represents the heights of fourteen basketball players, in inches. 69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 8
mamaluj [8]
If you would like to know the interquartile range of the new set and the interquartile range of the original set, you can do this using the following steps:
<span>The interquartile range is the difference between the third and the first quartiles.
The original set: </span>69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 82
Lower quartile: 72
Upper quartile: 76.25
Interquartile range: upper quartile - lower quartile = 76.25 - 72 = <span>4.25
</span>
The new set: <span>70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77
</span>Lower quartile: 72.5
Upper quartile: 76
Interquartile range: upper quartile - lower quartile = 76 - 72.5 = 3.5
The correct result would be: T<span>he interquartile range of the new set would be 3.5. The interquartile range of the original set would be more than the new set.</span>
Answer:
6000
Step-by-step explanation:
100x12= 1200+1200+1200+1200+1200=6000
Answer:
7³
Step-by-step explanation:
You could answer this after a quick inspection. 7 remains constant as t approaches 8. Each of the (t -1) terms will approach 7. So, multiplying these factors together, you'll get 7(7)(7) = 7³3 as your answer, the limit as t approaches 8 of the given expression.
Answer:
fhfhfhfhfhfhfhfhfhfhfhjffj
Step-by-step explanation:
tjttjtjtjtjtjtjtjtjtjtjtj