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joja [24]
3 years ago
12

What is the interquartile range for the data set? 4 , 7, 7, 3, 5, 2, 6, 7, 9

Mathematics
2 answers:
Brilliant_brown [7]3 years ago
7 0

Answer:

3.5

Step-by-step explanation:

Given: A data set as 4 , 7, 7, 3, 5, 2, 6, 7, 9

To find: The interquartile range for the data set

Solution: The interquartile range for the data set is the difference of the middle of the first half and the middle of the second half.

So, to find we first need to find the median.

The numbers can be arranged in ascending order as:

2, 3, 4, 5, 6, 7, 7, 7, 9

As, the number of terms is 9, which is odd. So, the median is \left ( \frac{9+1}{2} \right )^{th} term. So, the median is 6.

So, we have the first half as 2, 3, 4, 5 and the second half as 7, 7,. 7, 9.

Now, the middle of first half is \frac{3+4}{2} =3.5

middle of second half is \frac{7+7}{2} =7

Now, interquartile range=7-3.5=3.5

Hence, interquartile range is 3.5.

valina [46]3 years ago
4 0
Population size:9
Lower quartile (xL): 3.5
Upper quartile (xU): 7

<span>Interquartile range (xU-xL): 3.5</span>
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The graph of the equation 2x2 + xy + y2 = 4 is the tilted ellipse pictured below; i.e. the points (x,y) in the plane that satisf
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Answer:

The slope of tangent at point (1,-2) is \frac{2}{3}.

Step-by-step explanation:

The given equation of ellipse is

2x^2+xy+y^2=4

Differentiate both sides with respect to x.

\frac{d}{dx}(2x^2+xy+y^2)=\frac{d}{dx}(4)

\frac{d}{dx}(2x^2)\frac{d}{dx}(xy)+\frac{d}{dx}(y^2)=\frac{d}{dx}(4)

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(4x+y)+(x+2y)\frac{dy}{dx}=0

\frac{dy}{dx}=-\frac{4x+y}{x+2y}

Calculate the value of \frac{dy}{dx} at (1,-2).

\frac{dy}{dx}_{(1,-2)}=-\frac{4(1)+(-2)}{(1)+2(-2)}

\frac{dy}{dx}_{(1,-2)}=-\frac{2}{-3}

\frac{dy}{dx}_{(1,-2)}=\frac{2}{3}

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3 0
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Simora [160]

Answer:

$0.75

Step-by-step explanation:

Consider any one of the values given in the table.

Cost of 5 tickets = $3.75

So, cost of 1 ticket

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= $0.75

Verification:

Verify the answer by other values.

Cost of 10 tickets = $7.50

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= $7.50/10

= $0.75

Cost of 15 tickets = $11.25

So, cost of 1 ticket

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Cost of 20 tickets = $15.00

So, cost of 1 ticket

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= $0.75

The cost of 1 ticket is same in all cases.

Hence, verified.

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