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joja [24]
4 years ago
12

What is the interquartile range for the data set? 4 , 7, 7, 3, 5, 2, 6, 7, 9

Mathematics
2 answers:
Brilliant_brown [7]4 years ago
7 0

Answer:

3.5

Step-by-step explanation:

Given: A data set as 4 , 7, 7, 3, 5, 2, 6, 7, 9

To find: The interquartile range for the data set

Solution: The interquartile range for the data set is the difference of the middle of the first half and the middle of the second half.

So, to find we first need to find the median.

The numbers can be arranged in ascending order as:

2, 3, 4, 5, 6, 7, 7, 7, 9

As, the number of terms is 9, which is odd. So, the median is \left ( \frac{9+1}{2} \right )^{th} term. So, the median is 6.

So, we have the first half as 2, 3, 4, 5 and the second half as 7, 7,. 7, 9.

Now, the middle of first half is \frac{3+4}{2} =3.5

middle of second half is \frac{7+7}{2} =7

Now, interquartile range=7-3.5=3.5

Hence, interquartile range is 3.5.

valina [46]4 years ago
4 0
Population size:9
Lower quartile (xL): 3.5
Upper quartile (xU): 7

<span>Interquartile range (xU-xL): 3.5</span>
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An algebra test contains 38 problems. Some of the problems are worth 2 points each. The rest of the questions are worth 3 points
Naily [24]

Let 'x' be the problems worth 2 points.

Let 'y' be the problems worth 3 points.

Since, there are 38 total problems.

So, x+y =38 (equation 1)

x = 38-y

Since, a perfect score is 100 points.

So, 2x+3y = 100 (equation 2)

Substituting the value of 'x', we get

2(38-y)+3y=100

76-2y+3y=100

76+y = 100

y = 24

x+y = 38

x = 38-24 = 14

So, 14 problems are worth 2 points and 24 problems are worth 3 points.

5 0
3 years ago
Read 2 more answers
1. Find the vertex of the following: y = (x - 4)(x - 10) *
horsena [70]

Answer:

1. (7,-9)

2. (4,0) and (10,0)

3. (3,0) and (-3,0)

4. (0,-9)

5. (-1,-32)

Step-by-step explanation:

To find the vertex use the formula

\frac{-b}{2a}

First make the equation into a quadratic equation.

(x-4)(x-10)\\x^{2} -10x-4x+40\\x^{2} -14x+40

Now it is in the form

ax^{2} +bx+c=0

Now we can substitute the values

\frac{-(-14)}{2(1)} \\\frac{14}{2} \\7

Now we have 7 as our x value for the vertex we can substitute for y,

x^{2} -14x+40=y\\(7)^{2} -14(7)+40=y\\49-98+4=y\\y=-9

So the vertex for 1 is (7,-9)

To find the intercepts for 2 & 3, they basically already give it to you. You just need to find a value for x for x-4 that will equal it to 0 and another for x for x-10 that will equal it to 0.

x-4=0\\x=4\\\\x-10=0\\x=10

4 is slightly different but start the same,

(x-3)(x+3)\\x^{2}+3x-3x-9\\x^{2}-9

Here, c (9) just shows the graph move down 9, so the y intercept = 9.

5 is the same process as 1,

2(x-3)(x+5)\\2(x^{2}+5x-3x-15)\\2(x^{2}+2x-15)\\2x^{2}+4x-30

Vertex,

\frac{-(4)}{2(2)} \\\frac{-4}{4} \\-1

Substitute,

2x^{2}+4x-30\\2(-1)^{2}+4(-1)-30\\2-4-30\\-32

So the vertex is (-1,-32)

8 0
3 years ago
Wwat is 13+ R??.?.?.......My mom cant help me width it and she saied to go and ask Linda but she is in a meting
Lina20 [59]

Answer:

13R

Step-by-step explanation:

There is no factorable way to answer this equation

3 0
3 years ago
Help me plz! if you can
IgorLugansk [536]
Answer: 180/540
Simplified term would be 1/3
The answer is b
3 0
3 years ago
Add me as your friend
natka813 [3]

Answer:

no thank you

Step-by-step explanation:

3 0
3 years ago
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