A)
Let x represent the cost of 1 student, and y the cost of 1 teacher.
B)
In the first group, there's 25 students and 2 teachers. Their total cost is $97.50
So 25x + 2y = 97.50
In the second group, there's 32 students and 3 teachers. Their total cost is $127
So 32x + 3y = 127
We get the following system of equations:
25x + 2y = 97.50 (1)
32x + 3y = 127 (2)
C)
25x + 2y = 97.50 (1)
32x + 3y = 127 (2)
In equation (1)
25x + 2y = 97.50
25x + 2y - 2y = 97.50 - 2y
25x = 97.50 - 2y
25x / 25 = 97.50/25 - 2y/25
x = 3.9 - (2/25)y
In equation (2), let's replace x by its algebraic value
32x + 3y = 127
32(-2/25y + 3.9) + 3y = 127
11/25y + 124.8 = 127
11/25y + 124.8 - 124.8 = 127 - 124.8
11/25y = 2.2
(11/25y) / (11/25) = 2.2 / (11/25)
y = 5
x = -2/25y + 3.9
x = -2/25 * 5 + 3.9
x = 3.5
So the cost of each student is $3.5, and the cost of each teacher is $5.
Hope this helps! :)
The graph of an absolute value parent function is a pair of rays in quadrant 1 & 2, as shown in the graph.
The absolute value function is
f(x) = |x| or y = |x|
We also know that the absolute function can be wriiten as
y = |x|
=> y = x or y = -x
Comparing with y = mx + c
We get
m = 1 or m=-1 and c = 0
c = 0 implies that the line passes through the origin.
Hence the slopes shall be -1, 1 & the line passes through the origin.
Option A, B & D are the right answers.
The inequality you require is
The number of bottles left at the end of each day is 48 - 3x. So it is:-
48 - 3x < 10
Solving the inequality to find the last part of question:-
-3x < 10 - 48
-3x < -38
x > 38/3 = 12 2/3
So answer is 13 days.
2 shelves will display 2 cars because if 8 shelves display 1 car then there would be missing 4 cars to display and if you display 2 cars in one shelf you will need 2 shelves
