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11Alexandr11 [23.1K]
3 years ago
7

What is an equation of the line that passes through the point (-5,7) and is parallel

Mathematics
2 answers:
alukav5142 [94]3 years ago
6 0

Answer:

y=1/5 + 8

Step-by-step explanation:

I got it wrong from the previous answer c:

Brilliant_brown [7]3 years ago
4 0
Y=1/5x-3 you’re welcome
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Which of the following could be the graph of y = –xn where n is odd?
mina [271]

Answer:

Step-by-step explanation:

I think you meant y = -x^n, where ^ denotes exponentiation.

If n is odd, the graph begins in Quadrant II and decreases through the origin into Quadrant IV.  This is true of -x, -x^3, -x^5, and so on.

8 0
3 years ago
Help me please I don’t know how to do this !?!?
lesya692 [45]
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7 0
3 years ago
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Simple interest rate earned after 12 years on 1350 at an interest rate of 8%
Mademuasel [1]

Answer:

1296

Step-by-step explanation:

Simple interest is

I = PRT where I is the interest P is the principle, r is the rate and t is the time

I = 1350 * .08 * 12

I = 1296

8 0
4 years ago
Assume the annual interest rate is 6%. Calculate the value of an investment that pays $100 every two years, starting two
olganol [36]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
Which function has an asymptote at x= 39
LekaFEV [45]

Answer:

option B : f(x)= log_7(x-39)

Step-by-step explanation:

(a) f(x) = 7^{x-39}

For exponential function , there is no vertical asymptotes

General form of exponential function is

f(x) = n^{ax-b}+k

f(x) = 7^{x-39}

In the given f(x) the value of k =0

So horizontal asymptote is y=0

(b) lets check with option

f(x)= log_7(x-39)

To find vertical asymptote we set the argument of log =0  and solve for x

Argument of log is x-39

x-39=0 so x=39

Hence vertical asymptote at x=39


3 0
4 years ago
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