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mart [117]
3 years ago
9

Plants are set up in a greenhouse. 1/3 of potted plants are grown under red light, 1/3 under green light, and 1/3 under natural

light. plant biomass is measured at the beginning of the experiment and after a 28 day period. in this study, is the type of light an independent or dependent variable?
Mathematics
2 answers:
melomori [17]3 years ago
8 0
The type of light is an independent variable. The plant biomass is the dependant variable which depends of the type of light given.
Rudiy273 years ago
7 0

Answer:

Independent variable.

Step-by-step explanation:

In order to be able to recognize the dependent and independent variables you just have to read the problem and see which one depends on the other, in this case the light is the independent variable because depending on which light is installed the biomass would grow differently, not the other way around. So since the biomass depends on which light is installed, the light is independent.

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Measurements of the sodium content in samples of two brands of chocolate bar yield the following results (in grams):
Tpy6a [65]

Answer:

98% confidence interval for the difference μX−μY = [ 0.697 , 7.303 ] .

Step-by-step explanation:

We are give the data of Measurements of the sodium content in samples of two brands of chocolate bar (in grams) below;

Brand A : 34.36, 31.26, 37.36, 28.52, 33.14, 32.74, 34.34, 34.33, 29.95

Brand B : 41.08, 38.22, 39.59, 38.82, 36.24, 37.73, 35.03, 39.22, 34.13, 34.33, 34.98, 29.64, 40.60

Also, \mu_X represent the population mean for Brand B and let \mu_Y represent the population mean for Brand A.

Since, we know nothing about the population standard deviation so the pivotal quantity used here for finding confidence interval is;

        P.Q. = \frac{(Xbar -Ybar) -(\mu_X-\mu_Y)}{s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2}  } } ~ t_n__1+n_2-2

where, Xbar = Sample mean for Brand B data = 36.9

            Ybar = Sample mean for Brand A data = 32.9

              n_1  = Sample size for Brand B data = 13

              n_2 = Sample size for Brand A data = 9

              s_p = \sqrt{\frac{(n_1-1)s_X^{2}+(n_2-1)s_Y^{2}  }{n_1+n_2-2} } = \sqrt{\frac{(13-1)*10.4+(9-1)*7.1 }{13+9-2} } = 3.013

Here, s^{2}_X and s^{2} _Y are sample variance of Brand B and Brand A data respectively.

So, 98% confidence interval for the difference μX−μY is given by;

P(-2.528 < t_2_0 < 2.528) = 0.98

P(-2.528 < \frac{(Xbar -Ybar) -(\mu_X-\mu_Y)}{s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2}  } } < 2.528) = 0.98

P(-2.528 * s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} < (Xbar -Ybar) -(\mu_X-\mu_Y) < 2.528 * s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} ) = 0.98

P( (Xbar - Ybar) - 2.528 * s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} < (\mu_X-\mu_Y) < (Xbar - Ybar) + 2.528 * s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} ) = 0.98

98% Confidence interval for μX−μY =

[ (Xbar - Ybar) - 2.528 * s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} , (Xbar - Ybar) + 2.528 * s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} ]

[ (36.9 - 32.9)-2.528*3.013\sqrt{\frac{1}{13} +\frac{1}{9} , (36.9 - 32.9)+2.528*3.013\sqrt{\frac{1}{13} +\frac{1}{9} ]

[ 0.697 , 7.303 ]

Therefore, 98% confidence interval for the difference μX−μY is [ 0.697 , 7.303 ] .

                     

4 0
2 years ago
How are (5.3,1) and (-5.3,1) related?
OleMash [197]

Answer:

i think because theyre like terms, im not sure tho

3 0
2 years ago
I need help with this will be giving 10 points
dusya [7]

Answer:

Its D

Step-by-step explanation:

Both triangles are obtiuse rubber goose green mouse guva juice

8 0
2 years ago
Read 2 more answers
henry is mixing concrete. to make concrete he needs to mix cement, sand and gravel in the ratio 5 : 4 : 1 by weight. henry needs
MaRussiya [10]

Answer:

cement by 5 Kg

Step-by-step explanation:

add the parts of the ratio, 5 + 4 + 1 = 10 parts

Divide the quantity of concrete by 10 to find the value of one part of the ratio.

110Kg ÷ 10 = 11Kg ← value of 1 part of ratio , thus

5 parts = 5 × 11Kg = 55Kg ← cement required

4 parts = 4 × 11Kg = 44Kg  ← sand required

1 part = 11Kg ← gravel required

He requires 55Kg of concrete but only has 50Kg.

He requires 44Kg of sand and has 55Kg

He requires 11Kg of gravel and has 15Kg

Thus he is 5Kg short of cement.

7 0
3 years ago
Dexter is curious as to whether there is a relationship between a person’s height and thumb length. Fourteen of his classmates v
love history [14]

The answer to this question is 7.404

3 0
3 years ago
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