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mart [117]
3 years ago
9

Plants are set up in a greenhouse. 1/3 of potted plants are grown under red light, 1/3 under green light, and 1/3 under natural

light. plant biomass is measured at the beginning of the experiment and after a 28 day period. in this study, is the type of light an independent or dependent variable?
Mathematics
2 answers:
melomori [17]3 years ago
8 0
The type of light is an independent variable. The plant biomass is the dependant variable which depends of the type of light given.
Rudiy273 years ago
7 0

Answer:

Independent variable.

Step-by-step explanation:

In order to be able to recognize the dependent and independent variables you just have to read the problem and see which one depends on the other, in this case the light is the independent variable because depending on which light is installed the biomass would grow differently, not the other way around. So since the biomass depends on which light is installed, the light is independent.

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Find the measure of the angle shown by the arrow(in radians)
soldi70 [24.7K]

Answer:

-7π/3 or -420 degrees

Step-by-step explanation:

So we know that the arrow has made one full rotation and that it is moving in a clockwise direction. So already we have -2π degrees.

The arrow stops at π/6 before the next π/2 rotation. Therefore we find the difference between the two.

π/2 - π/6

3π/6 - π/6 = 2π/6

π/3

Since this is still clockwise, we make this negative. So the measure of the angle shown by the arrow is -2π - π/3

8 0
3 years ago
Brainliest if correct
n200080 [17]

Answer:

16 and 125

Step-by-step explanation:

-2*-2 = 4

4*-2 = -8

-8*-2 = 16

5*5 = 25

25*5 = 125

6 0
2 years ago
This building consists of two rectangular prisms-a small space for offices and an attached larger space for warehouse storage. H
Naily [24]
I would have to know the space of the two rectangular prisms to answer this correctly
6 0
3 years ago
the vertex of this parabola is at (3,-2). When the x-vaue is 4, the y-value is 3. What is the coefficient of the squared express
bixtya [17]
<h3>Answer:   5</h3>

=========================================================

Explanation:

Vertex form is

y = a(x-h)^2 + k

We are told the vertex is (3,-2), so we know (h,k) = (3,-2)

y = a(x-h)^2 + k will update to y = a(x-3)^2 - 2

--------

Then we also know that (x,y) = (4,3) is a point on the parabola. Plug those x and y values into the equation and solve for 'a'

y = a(x-3)^2 - 2

3 = a(4-3)^2 - 2

3 = a(1)^2 - 2

3 = a - 2

3+2 = a

5 = a

a = 5

This is the coefficient of the x^2 term since the standard form is y = ax^2+bx+c.

4 0
2 years ago
Please help me I can’t figure them out
OLga [1]
Where is the question
8 0
3 years ago
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