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3 years ago

Be safe stay home and we will get through this all of us thank you for support!!!!!!

Mathematics

2 answers:

Alona [7]3 years ago

8 0

Answer:

Thank you for the encouragement!

Step-by-step explanation:

Though try to keep it in the right subject

Thepotemich [5.8K]3 years ago

3 0

Answer: TYSMM YOU TOOOOO AND WASH YOUR HANDS !!!

Step-by-step explanation:

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What is a unit fraction?

guapka [62]

Answer:

denominator

Step-by-step explanation:

the upper part is numerator

so the lower is denominator

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2 years ago

Using the function, g(x) = 5x - 2 and the domain below, state the range.

Rom4ik [11]

joke 1. 2 hunters were out in the woods right while they were following fresh tracks from a big elk one of the hunters drop to the ground and his eyes roll backwards so the other hunter whips out his phone and calls the hospital "I THINK MY FRIEND IS DEAD!" he told the doctor the doctor told him " Calm down let's make sure he's dead. so there is a moment of silence the you here a big pop the hunter says "NOW WHAT!" (he shot his friend)

joke 2. I wanted to be a democrat for halloween but i could not stick my head far enough up my a/s/s to be one.

brainliest for being funny?

5 0

3 years ago

Read 2 more answers

Find the sum.<br> 2y<br> y2 + 2y + 1<br> +4/<br> y2 + 3y + 2

Sladkaya [172]

Answer:

did u put the equation right?

5 0

2 years ago

Analyze the diagram below and complete the instructions that follow.

shutvik [7]

Answer:

there is no diagram ......

6 0

3 years ago

A ball is thrown vertically in the air with a velocity of 95 ft/s. The ball is at a height of 120 ft.

sattari [20]

Answer:

The ball is at a height of 120 feet after 1.8 and 4.1 seconds.

Step-by-step explanation:

The statement is incomplete. The complete statement is perhaps the following "A ball is thrown vertically in the air with a velocity of 95 ft/s. What time in seconds is the ball at a height of 120ft. Round to the nearest tenth of a second."

Since the ball is launched upwards, gravity decelerates it up to rest and moves downwards. The position of the ball can be determined as a function of time by using this expression:

$y = y_{o} + v_{o}\cdot t +\frac{1}{2}\cdot g \cdot t^{2}$

Where:

$y_{o}$ - Initial height of the ball, measured in feet.

$v_{o}$ - Initial speed of the ball, measured in feet per second.

$g$ - Gravitational constant, equal to $-32.174\,\frac{ft}{s^{2}}$ .

$t$ - Time, measured in seconds.

Given that $y_{o} = 0\,ft$ , $v_{o} = 95\,\frac{ft}{s}$ , $g = -32.174\,\frac{ft}{s^{2}}$ and $y = 120\,ft$ , the following second-order polynomial is found:

$120\,ft = 0\,ft + \left(95\,\frac{ft}{s} \right)\cdot t +\frac{1}{2}\cdot \left(-32.174\,\frac{ft}{s^{2}} \right) \cdot t^{2}$

$-16.087\cdot t^{2} + 95\cdot t -120 =0$

The roots of this polynomial are, respectively:

$t_{1} \approx 4.075\,s$ and $t_{2} \approx 1.831\,s$ .

Both roots solutions are physically reasonable, since $t_{1}$ represents the instant when the ball reaches a height of 120 ft before reaching maximum height, whereas $t_{2}$ represents the instant when the ball the same height after reaching maximum height.

In nutshell, the ball is at a height of 120 feet after 1.8 and 4.1 seconds.

8 0

3 years ago