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goblinko [34]
3 years ago
11

The mass of one electron is 9.11 x 10^-28 what is the mass of 1.00 mole of electrons

Chemistry
1 answer:
Vlad1618 [11]3 years ago
6 0
<span>You have the answer and you don’t even know it. Just take the inverse of what one electron weights in grams (9.11E-28) to get the number of electrons in one gram. You should get an astonishing large number (1.10E+27). Just in case you do not recognize the notation it is scientific notation as a calculator would write it.</span>
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German scientist alfred wiener is best known for what hypothesis?
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He was best known for the Continental Drift 
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How is a mineral's effervescence measured?
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Dripping Acid onto it
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4 years ago
2. For the reaction, 2SO2(g) + O2(g) 2SO3(g), at 450.0 K the equilibrium con¬stant, Kc, has a value of 4.62. A system was charge
miv72 [106K]

Answer:

Q >> Kc

We have more products than reactans. To reach the equilibrium, the balance will shift to the left.

Explanation:

Step 1: Data given

Temperature = 450.0 K

Kc = 4.62

When Kc > Q, we have more reactants than products. To reach the equilibrium, the balance will shift to the right

When Kc < Q, we have more products than reactans. To reach the equilibrium, the balance will shift to the left.

When Kc = Q,the equiation isatequilibrium

[SO3] = 0.254 M

[O2] = 0.00855 M

[SO2] = 0.500 M

Step 2: The balanced equation

2SO2(g) + O2(g) ⇄ 2SO3(g)

Step 3: Calculate the Q

Q = [SO3]² / [O2][SO2]²

Q = 0.254²/ (0.500 * 0.00855²)

Q = 1765

Q >> Kc

We have more products than reactans. To reach the equilibrium, the balance will shift to the left.

6 0
4 years ago
Read 2 more answers
The enthalpy of combustion of benzoic acid (C6H5COOH) is commonly used as the standard for calibrating constant-volume bomb calo
Anit [1.1K]
<h3>Answer:</h3>

28.96 kJ/°C

<h3>Explanation:</h3>

We are given;

  • Enthalpy change (ΔH) = −3226.7 kJ/mol
  • The reaction is exothermic since the heat change is negative;
  • Mass of benzoic acid = 3.1007 g
  • Temperature change (21.84°C to 24.67°C) = 2.83°C

We are required to find the heat capacity of benzoic acid;

<h3>Step 1: Moles of benzoic acid </h3>

Moles = Mass ÷ molar mass

Molar mass of benzoic = 122.12 g/mol

Therefore;

Moles = 3.1007 g ÷ 122.12 g/mol

          = 0.0254 moles

<h3>Step 2: Determine the specific heat capacity </h3>

Heat change for 1 mole = 3226.7 kJ

Moles of Benzoic acid = 0.0254 moles

But;

Specific heat capacity × ΔT = Moles × Heat change

  cΔT = nΔH

Therefore;

Specific heat capacity,c = nΔH ÷ ΔT

                                     = (3226.7 kJ × 0.0254 moles) ÷ 2.83°C

                                    = 28.96 kJ/°C

Therefore, the specific heat capacity of benzoic acid is 28.96 kJ/°C

7 0
4 years ago
Calculate the vapor pressure of water above a solution prepared by dissolving 28.5 g of glycerin (c3h8o3) in 135 g of water at 3
pshichka [43]
Data:

<span>Solute: 28.5 g of glycerin (C3H8O3)
Solvent: 135 g of water at 343 k.
Vapor pressure of water at 343 k: 233.7 torr.

Quesiton: Vapor pressure of water

Solution:

Raoult's Law: </span><span><span>The vapour pressure of a solution of a non-volatile solute is equal to the vapour pressure of the pure solvent at that temperature  multiplied by its mole fraction.

Formula: p = Xsolvent * P pure solvent

X solvent = moles solvent / moles of solution

molar mass of H2O = 2*1.0g/mol + 16.0 g/mol = 18.0 g/mol

moles of solvent = 135 g of water / 18.0 g/mol = 7.50 mol

molar mass of C3H8O3 = 3*12.0 g/mol + 8*1 g/mol + 3*16g/mol = 92 g/mol

moles of solute = 28.5 g / 92.0 g/mol = 0.310 mol

moles of solution = moles of solute + moles of solvent = 7.50mol + 0.310mol = 7.810 mol

Xsolvent = 7.50mol / 7.81mol = 0.960

p = 233.7 torr * 0.960 = 224.4 torr

Answer: 224.4 torr
</span> </span>
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