To determine the amount of 6.0 M H2SO4 needed for the preparation, equate the number of moles of the 6.0 M and 2.5 M H2SO4 solution. This is done as follows
M1 x V1 = M2 x V2
Substituting the known variables,
(6.0 M) x V1 = (2.5 M) x (4.8 L)
Solving for V1 gives an answer of V1 = 2 L. Thus, to prepare the needed solution, dilute 2 L of 6.0 M H2SO4 solution with water until the volume reach 4.8 L.
Answer: Density (ρ) = 1.25 gram/liter
Explanation:
= 1.25 gram/liter
Answer:
mass of oxygen = 80.077 grams
Explanation:
From the periodic table, we can find that:
atomic mass of oxygen = 16 grams
atomic mass of phosphorus = 30.97 grams
The balanced equation is:
4P + 5O₂ ..............> 2P₂O₅
From this balanced equation we can note that:
4 moles of P are required to react with 5 moles of O₂
This means that:
4 * 30.97 = 123.88 grams
are required to react with
5 * (16*2) = 160 grams
Therefore, to know the mass of oxygen required to react with 62 grams of phosphorus, all we have to do is cross multiplication as follows:
123.88 grams of phosphorus ..................> 160 grams of oxygen
62 grams of phosphorus .........................> ?? grams of oxygen
mass of oxygen = (62*160) / (123.88) = 80.077 grams
Hope this helps :)
Answer:
the branch of biology that deals with the relations of organisms to one another and to their physical surroundings.
Explanation:
Answer:
Synthesis reaction
Explanation:
S8 + 4Si → 2Si2S4 Would be a synthesis reaction
