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lesya [120]
3 years ago
14

What mass of H2 gas (in g. would be produced by the complete reaction of the aluminum block?

Chemistry
1 answer:
loris [4]3 years ago
3 0

First lets calculate the moles of aluminum (molar mass is 27 gram/mol):

n = m/M = 14.9 / 27 = 0.551 mole of Al


According to the reaction between sulfuric acid and aluminum:

From 2 moles of aluminum ==> we get 3 moles of Hydrogen gas

so, let's do cross multiplication

0.551 ==> 0.551 * 3/2 = 0.83 mole of H2


So, from this reaction we got 0.83 mole of H2 gas

knowing that the molar mass of H2 is 2 gram/mol, the mass of the gas is.

m = n * M = 0.83 * 2 = 1.66 gram of H2


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118g of o2 gas is held at STP what is the volume of gas
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3 years ago
What is the percent yield of a reaction in which 47.5 g tungsten (VI) oxide (WO3) reacts with excess hydrogen gas to produce met
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Answer:

The percent yield of a reaction is 85.04%

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:WO_3+3H_2\rightarrow W+3H_2O

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Molar mass of WO_3 = 232 g/mole

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Volume of water obtained from the reaction , V= 9.40mL

Mass of water = m = Experimental yield of water

Density of water = d = 1.00 g/mL

M=d\times V = 1.00 g/mL\times 9.40 mL=9.40 g

Moles of tungsten(VI) oxide =\frac{47.5 g}{232 g/mol}=0.2047 mol

According to recation 1 mole of tungsten(VI) oxide gives 3 moles of water, then 0.2047 moles of tungsten(VI) oxide will give:

\frac{3}{1}\times 0.2047 mol=0.6141 mol

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To calculate the percentage yield of reaction , we use the equation:

% yield = {\frac{Experimental yield}{theoretical yield} \times 100

\frac{9.40}{11.054} \times 100\\\\= 85.04

The percent yield of a reaction is 85.04%

7 0
3 years ago
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