Answer:
The probability of rolling a sum greater than 1 when rolling two fair numbered cube is 1 or 36/36.
Step-by-step explanation:
There is no 1 as a sum when rolling two fair numbered cubes, so all the sums will be greater than 1.
Well, the answer will depend on whether the order will count or not (based on Permutations and Combinations). <em>If the order counts</em>, then we would use the formula for Permutations, which is:

Where n is the number of items you have, and r is the number of times you choose from the items.

Which simplifies to

Which simplifies to 15*14*13 (because all the numbers 1-12 in the factorial canceled out), which gets us the answer
2730.
Now, if you wanted to find the number of ways to order the toys without replacement (<em>order doesn't count</em>), you would use the formula:

The variables are still the same, but you are now multiplying by r!.

Simplifies to

Which simplifies to (using the same cancellation method above)

Dividing 2730 by 3! will get us an answer of
455.
Really, it depends on whether they are ordered or not. In this case (since you didn't specify whether the order mattered), the answer would be
455 or
2730.
:)
<span>∠ABC ∠BAD is the correct answer
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