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Irina-Kira [14]
3 years ago
8

A survey found that 35% of callers complain about the service they receive from a call center. Assume that the events of differe

nt calls resulting in a complaint are independent. What is the probability that two out of the next five calls produce a complaint?
Mathematics
1 answer:
sasho [114]3 years ago
6 0

Answer:

0.336 or 33.6%

Step-by-step explanation:

It follows from the question that the probability of a complaint is 35% = 35/100 = 0.35. Let's call this probability, p.

The probability of no complaint is mutually exclusive of p since both are complements. Let's call this q. Then

q = 1 - p = 1 - 0.35 = 0.65

The distribution is a binomial distribution.

Events of each call are independent.

The probability of 2 calls with complaint out of 5 is

\binom{5}{2}p^2 \timesq^3=10\times0.35^2\times0.65^3 = 0.336 = 33.6\%

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Answer:

a) P(male=blue or female=blue) = 0.71

b) P(female=blue | male=blue) = 0.68

c) P(female=blue | male=brown) = 0.35

d) P(female=blue | male=green) = 0.31

e) We can conclude that the eye colors of male respondents and their partners are not independent.

Step-by-step explanation:

We are given following information about eye colors of 204 Scandinavian men and their female partners.

              Blue    Brown     Green    Total

Blue        78         23            13          114

Brown     19         23            12          54

Green     11           9             16          36

Total      108       55            41          204

a) What is the probability that a randomly chosen male respondent or his partner has blue eyes?

Using the addition rule of probability,

∵ P(A or B) = P(A) + P(B) - P(A and B)

For the given case,

P(male=blue or female=blue) = P(male=blue) + P(female=blue) - P(male=blue and female=blue)

P(male=blue or female=blue) = 114/204 + 108/204 − 78/204

P(male=blue or female=blue) = 0.71

b) What is the probability that a randomly chosen male respondent with blue eyes has a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=blue) = 78/114

P(female=blue | male=blue) = 0.68

c) What is the probability that a randomly chosen male respondent with brown eyes has a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=brown) = 19/54

P(female=blue | male=brown) = 0.35

d) What is the probability of a randomly chosen male respondent with green eyes having a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=green) = 11/36

P(female=blue | male=green) = 0.31

e) Does it appear that the eye colors of male respondents and their partners are independent? Explain

If the following relation holds true then we can conclude that the eye colors of male respondents and their partners are independent.

∵ P(B | A) = P(B)

P(female=blue | male=brown) = P(female=blue)

or alternatively, you can also test

P(female=blue | male=green) = P(female=blue)

P(female=blue | male=blue) = P(female=blue)

But

P(female=blue | male=brown) ≠ P(female=blue)

19/54 ≠ 108/204

0.35 ≠ 0.53

Therefore, we can conclude that the eye colors of male respondents and their partners are not independent.

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Rihanna must put a five dollar deposit down to buy a necklace. If P where presents the full price of the necklace which expressi
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Answer:

<em>The expression is </em><em>P - 5</em>

Step-by-step explanation:

Rihanna already made a deposit of $5 to buy the necklace (given)

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Full price of necklace = amount paid + amount left to pay

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m = P - 5

Therefore, the amount Rihanna owes before tax = P - 5

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