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ExtremeBDS [4]
3 years ago
15

Find the measure of DF

Mathematics
1 answer:
WITCHER [35]3 years ago
4 0

Answer:

144 = arc DF

Step-by-step explanation:

Inscribed Angle = 1/2 Intercepted Arc

72 = 1/2  arc DF

Multiply by 2

2*72 = arc DF

144 = arc DF

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You pay $7.80 for 6 pounds of apples. Find the price per pound.
Morgarella [4.7K]

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▹ Answer

<em>$1.30</em>

<em></em>

▹ Step-by-Step Explanation

To find the price per pound, you have to divide the total amount of money by the amount of pounds:

$7.80/6 lbs = $1.30

Hope this helps!

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8 0
3 years ago
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The London theater offers child tickets at 10$each and adult tickets at 20$ each.Mrs burham buys 34 tickets at a total cost of 5
kirill115 [55]

Answer:

A+C=34

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4 0
3 years ago
I need the answer for this exact question
denis23 [38]

Answer:

y=\frac{7}{2}x-20

Step-by-step explanation:

Let the equation of the line be y-y_1=m(x-x_1) where, 'm' is its slope and (x_1,y_1) is a point on it.

Given:

The equation of a known line is:

y=-\frac{2}{7}x+9

A point on the unknown line is:

(x_1,y_1)=(4,-6)

Both the lines are perpendicular to each other.

Now, the slope of the known line is given by the coefficient of 'x'. Therefore, the slope of the known line is m_1=-\frac{2}{7}

When two lines are perpendicular, the product of their slopes is equal to -1.

Therefore,

m\cdot m_1=-1\\m=-\frac{1}{m_1}\\m=-\frac{1}{\frac{-2}{7} }=\frac{7}{2}

Therefore, the equation of the unknown line is determined by plugging in all the given values. This gives,

y-(-6))=\frac{7}{2}(x-4)\\y+6=\frac{7}{2}x-14\\y=\frac{7}{2}x-14-6\\\\y=\frac{7}{2}x-20

The equation of a line perpendicular to the given line and passing through (4, -6) is y=\frac{7}{2}x-20.

3 0
3 years ago
A huge ice glacier in the Himalayas initially covered an area of 454545 square kilometers. Because of changing weather patterns,
guajiro [1.7K]

We have been given that a huge ice glacier in the Himalayas initially covered an area of 45 square kilo-meters. The relationship between A, the area of the glacier in square kilo-meters, and t, the number of years the glacier has been melting, is modeled by the equation A=45e^{-0.05t}.

To find the time it will take for the area of the glacier to decrease to 15 square kilo-meters, we will equate A=15 and solve for t as:

15=45e^{-0.05t}

\frac{15}{45}=\frac{45e^{-0.05t}}{45}

\frac{1}{3}=e^{-0.05t}

Now we will switch sides:

e^{-0.05t}=\frac{1}{3}

Let us take natural log on both sides of equation.

\text{ln}(e^{-0.05t})=\text{ln}(\frac{1}{3})

Using natural log property \text{ln}(a^b)=b\cdot \text{ln}(a), we will get:

-0.05t\cdot \text{ln}(e)=\text{ln}(\frac{1}{3})

-0.05t\cdot (1)=\text{ln}(\frac{1}{3})

-0.05t=\text{ln}(\frac{1}{3})

t=\frac{\text{ln}(\frac{1}{3})}{-0.05}

t=\frac{\text{ln}(\frac{1}{3})\cdot 100}{-0.05\cdot 100}

t=\frac{\text{ln}(\frac{1}{3})\cdot 100}{-5}

t=-\text{ln}(\frac{1}{3})\cdot 20

t=-(\text{ln}(1)-\text{ln}(3))\cdot 20

t=-(0-\text{ln}(3))\cdot 20

t=20\text{ln}(3)

Therefore, it will take 20\text{ln}(3) years for area of the glacier to decrease to 15 square kilo-meters.

6 0
3 years ago
What is the midpoint of the segment shown below? Pls help
Leno4ka [110]

Answer:

its a slope....

Step-by-step explanation:

4 0
3 years ago
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