Answer:
We are 95% confident that the true weight of the rock is between 25.2 g and 29.1 g.
Step-by-step explanation:
Hello!
A geology student weighted a rock 5 times and estimated the average weight using a 95% CI [25.2; 29.1]gr
The confidence interval is used to estimate the value of the population mean, it gives you a range of values for it.
The 95% level of confidence of the interval indicates that if you were to construct 100 confidence intervals to estimate the population mean, you'd expect 95 of them to include the true value of the parameter.
So with a 95% confidence level, you'd expect the true average weight of the rock to be included in the interval [25.2; 29.1]gr
I hope this helps!
4(2x^2+3y^2)^2 = 16x^4 + 48x^2y^2 + 36y^4
(4x-5)(16x^2 + 20x + 25) = 64x^3 - 125
4 ( 2x^2 + 3y^2)(2x^2 - 3y^2) = 16x^4 -36y^4
hope that helps
For this case, the first thing we must do is define variables.
We have then:
x = pounds of type a coffee
y = pounds of type b coffee
We now write the system of equations:
5.95x + 4.45y = 490.05
y = 2x
Solving the system of equations we have:
x = 33
y = 66
Answer:
were used 33 pounds of type a coffee
Simple Interest , I = PRT/100
Where P = Principal, R = Rate, T = Time in years
Time, T = (100*I)/(P*R)
T = 100* 84 / (600 * 7) Use your calculator
T = 2
Time is 2 years.
Answer:
4,000,000
Step-by-step explanation:
There are 1,000 grams in a kilogram
So, multiply 4,000 x 1,000
And you get 4,000,000
