2 years ago

What are the intercepts of y=4x-2?

1 answer:

8 0

First, solve for the x - intercept. To do so, equate y to 0 and solve for x.

0 = 4x - 2, x = 1/2

Second, solve for the y - intercept. Equate x to 0 which will give us,

y = (4)(0) -2, y = -2

Therefore, the x-intercept is 1/2 and y-intercept is -2.

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</span>
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$f(x) = \frac{3x^2 + x - 4}{x-1} \\ f(x) = \frac{3x^2 + 4x - 3x - 4}{x-1} \\ f(x) = \frac{x(3x+4)-1(3x+4)}{x-1} \\ f(x) = \frac{(x-1)(3x+4)}{(x-1)} \\ f(x) = 3x+4 \\ now ~ insert ~ x=1: \\ f(1) = 3(1) + 4 = 7 \\ It~means~discontinuity~at~(1,7).\\ Now~let~us~find~zeros.\\ put~ f(x) = 3x+4 ~ equals~ to ~zero. \\ =\ \textgreater \ ~3x+4 = 0 \\ =\ \textgreater \ ~ x = \frac{-4}{3} \\ Hence~zeros=( \frac{-4}{3}, 0)$

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