Answer:
0.050V
Explanation:
To solve this problem it is necessary to use the concepts related to the potential between two objects that have a magnetic field, this concept is represented in the equation.

Where,
v= tangencial velocity
B = Magnetic Field
We know for definition that,

Where,
L = length
Angular velocity
We can replace this values in our first equation then,

Integrating we have,

Replacing the values,


Therefore the potential difference between the center of the rod and the other rod is 0.050V
Answer:
y = 27 cm
Explanation:
given,
After 11 hours of burning height of candle is 27.9 cm
After 30 hours of burning height of candle is 26 cm
height after 20 hour = ?
the candle height decreases linearly
using linear equation
y = m x+ c
27.9 = m (11 ) + C.......(1)
26 = m (30) + C..............(2)
on solving equation (1) and (2)
1.9 = -19 m
m = -0.1
from equation 2
26 = -3 + C
C = 29
y = m x + 29
at 20 hour
y = -0.1× 20 + 29
y = 27
height of candle after 20 hours is 27 cm.
Answer:
A. Its translational kinetic energy is larger than its rotational kinetic energy.
Explanation:
Given that
Radius = R
Mass = M
We know that mass moment of inertia for the solid sphere

Lets take angular speed =ω
Linear speed =V
Condition for pure rolling , V= ω R
Rotation energy ,RE





RE= 0.2 MV²
The transnational kinetic energy TE

TE= 0.5 MV²
From above we can say that transnational energy is more than rotational energy.
Therefore the answer is A.
The picture isn’t clear so I can’t read the dimensions of the box but I can try my best to guide u through the question.
For part a u need to find the volume of the box as that will equal the volume of sand that can be filled inside.
For this u multiply the height, width and length of the box.
For part b the mass of sand alone will be
=Mass of box + sand - Mass of empty box
=216 - 40
=176 grams
For part c the density of sand can be calculated by the formula
Density= Mass/Volume
So the mass (176g) / volume from part a
For part d u need to know that something will float if it has a lower density than what it is floating in. If the final density of sand that was found in part c is less than the density of gold (19.3 g/cm^3) it will float. Otherwise it will sink.
Hope this helped!