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avanturin [10]
3 years ago
9

Suppose that the height (in centimeters) of a candle is a linear function of the amount of time (in hours) it has been burning.

After 11 hours of burning, a candle has a height of 27.9 centimeters. After 30 hours of burning, its height is 26 centimeters. What is the height of the candle after 20 hours?
Physics
1 answer:
iragen [17]3 years ago
3 0

Answer:

y = 27 cm

Explanation:

given,

After 11 hours of burning height of candle is 27.9 cm

After 30 hours of burning height of candle is 26 cm

height after 20 hour = ?

the candle height decreases linearly

using linear equation

y = m x+ c

27.9 = m (11 ) + C.......(1)

26 = m (30) + C..............(2)

on solving equation (1) and (2)

1.9 = -19 m

m = -0.1

from equation 2

26 = -3 + C

C = 29

y = m x + 29

at 20 hour

y = -0.1× 20 + 29

y = 27

height of candle after 20 hours is 27 cm.

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y = 6.62 * 10E-34 / (2 * 9.1 * 10E-31 * 3 * 10E8)  m

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4 0
3 years ago
An archer shoots an arrow with a mass of 45.0 grams from bow pulled
Sladkaya [172]

Answer:

The force the archer need to pull in order to achieve the height is approximately 101.8 N

Explanation:

By energy conservation principle, puling an elastic bow with a force, for a given distance, performs work which is converted to the potential energy of the arrow at height

The given parameters are;

The mass of the arrow, m = 45.0 grams = 0.045 kg

The distance the elastic bow is pulled, d = 65.0 cm = 0.65 m

The height at which the arrow is reaches, h = 150.0 meters

Let 'F', represent the force the archer need to pull in order to achieve the height

Work done, W = Force × Distance moved in the direction of the force

Therefore;

The work done in pulling the arrow, W = F × d

By energy conservation, we have;

The work done in pulling the arrow, W = The potential energy gained by the arrow, P.E.

W = P.E.

The potential energy gained by the arrow, P.E. = m·g·h

Where;

m = The mass of the arrow

g = The acceleration due to gravity = 9.8 m/s²

h = The height the arrow reaches

∴ by plugging in the values, P.E. = 0.045 kg ×9.8 m/s² × 150 m = 66.15 J

W = F × d = F × 0.065 m

Also, W = P.E. = 66.15 J

∴ W = F × 0.065 m = 66.15 J

F × 0.065 m = 66.15 J

F = 66.15 J/(0.65 m) = 1323/13 N ≈ 101.8 N

The force the archer need to pull in order to achieve the height, F ≈ 101.8 N.

3 0
2 years ago
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