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Leokris [45]
4 years ago
6

Write an expression for 8 increased by g

Mathematics
2 answers:
ICE Princess25 [194]4 years ago
7 0
Your answer could be 8+g or g+8 either one will work.
GuDViN [60]4 years ago
6 0
8+g 
 
that is the expressioin!!
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For his long distance phone service, Chris pays a $2 monthly fee plus 12 cents per minute. Last month, Chris's long distance bil
photoshop1234 [79]
Use the terms and variables given to find an equation to find the answer.
Price= $2 + .12xminutes
P=2+0.12m

Then, plug in known variables to find the final answer.
15.08=2+0.12m
13.08=.12m
m=13.08/.12
m=109 minutes
4 0
4 years ago
Ok so I now fix it, can you help me?
11Alexandr11 [23.1K]

Answer:

1 80%

2 80%

3 80%

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
A pony weighed 313.3 kilograms in March, 348.2 kilograms in April, and 364.6 kilograms in May. How much weight did the pony gain
olchik [2.2K]

Answer:

C. 51.3 kg

Step-by-step explanation:

Calculation for How much weight did the pony gain from March to May

Weight gain from March to May=364.6 kilograms-313.3 kilograms

Weight gain from March to May=51.3 kg

Therefore the weight that the pony gain from March to May will be 51.3kg

6 0
3 years ago
Can someone please give me step by step using pemdas I will give I brilliant
Tasya [4]

Answer: 24

Step-by-step explanation: so you calculate everything in the parenthesis fist so you do (5-1+3) to (4+3)  then you do (4+3=7)

so this is how your equation is going to look 10+4÷2×7 then your going to do 4 divied by 2=2 then your going to do 2*7=14 and 14+10=24

STEP ONE- 10+4÷2(4+3)

STEP TWO- 10+4÷2×7

STEP THREE-10+2×7

STEP FOUR-10+14

ANSWER is 24

hope this helps :)

3 0
3 years ago
7. Verify the following: i) (ab + bc) (ab – bc) + (bc + ca) (bc – ca) + (ca + ab) (ca – ab) = 0 ii) (a + b + c) (a² + b² + c² –
blsea [12.9K]

<u>1</u><u>.</u><u> </u><u>(ab + bc) (ab – bc) + (bc + ca) (bc – ca) + (ca + ab) (ca – ab) = 0</u>

We know that (a+b)(a-b) = a²-b²

(ab + bc)(ab -bc) can be written as a²b² - b²c²

(bc + ca)(bc -ca) can be written as b²c² - c²a²

(ca + ab)(ca - ab) can be written as c²a² - a²b²

→ a²b² - b²c² + b²c² - c²a² + c²a² - a²b²

→ a²b² - a²b² - b²c² + b²c² - c²a² + c²a²

→ 0

<u>2</u><u>.</u><u> </u><u>(a + b + c) (a² + b² + c² – ab – bc – ca) = a³ + b³+ c³ – 3abc</u>

→ a³ + ab² + ac² -a²b - abc -ca² + a²b + b³ + bc² - ab² - b²c - abc + a²c + b²c + c³ - abc - bc² - c²a

→ a³ + b³+ c³ + (- abc - abc - abc) + (ab² - ab² )+ (ac² - ca² ) -(a²b + a²b )+ (bc² - bc² )+ (a²c - c²a) + (b²c - b²c)

→ a³+b³+c³ - 3 abc .

<u>3</u><u>.</u><u> </u><u>(p – q) (p² + pq + q²) = p³ – q³. </u>

→ p³ + p²q + pq² - p²q - pq² - q³

→ p³ - q³ +(p²q - p²q) + (pq² - pq²)

→ p³ - q³

7 0
4 years ago
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