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viktelen [127]
3 years ago
14

What is the solution of 2p-14=4(p+5)

Mathematics
1 answer:
Pavel [41]3 years ago
8 0
2p-14=4(p+5) Step 1, parentheses 2p-14=4p+20 Subtract 20 from each side of the equation 2p-34=4p Subtract 2p from each side -34=2p Divide each side by 2 -17=p
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Please help it's due today!!!!!!
BlackZzzverrR [31]

Answer:

See Below

Step-by-step explanation:

We are given 3 equations.

3x + 8

5x - 20

and

5x + 4y

First lets solve for x using the first two

3x + 8 = 5x -20

Move the variables to one side

3x + 8 = 5x -20

-3x        -3x

8 = 2x -20

+20     +20

28 =2x

28/2 =2x /2

14 = x

Now we have x = 14

Lets plug this into the second equation to solve for the angle

3(14) + 8

42 + 8 = 50

5(14) - 20

70 - 20 =50

Now, lets plug the x and the angle into the third equation to find y

5 (14) +4y = 50

70 + 4y = 50

-70           -70

4y = -20

4y/4 = -20/4

y = -5

So now we have:

x = 14

y = -5

and the angle = 50

Hope this helps!

6 0
3 years ago
PLS HELP ME GRADUATE ILL MARK BRAINLY A-AND ILL GIVE U A COOKIE!!! PLS
snow_lady [41]

Answer:

Dilate circle A by a scale factor of 4.

Step-by-step explanation:

Dilating circle A by 4 would be the same as multiplying its radius of 6 by 4, which would make it 24.

The radius of circle B is 24.

Rotating it wouldn't change anything (it's a circle), and I don't think reflecting and translating show circle similarity

6 0
3 years ago
Jkl is an equilateral triangle jk= 13x+5,KL= 17X-19 AND JL= 8X+35​
stira [4]

Answer:

x = 6

Step-by-step explanation:

Since the triangle is equilateral then sides are congruent.

Equate any 2 sides and solve for x

13x + 5 = 8x + 35 ( subtract 8x from both sides )

5x + 5 = 35 ( subtract 5 from both sides )

5x = 30 ( divide both sides by 5 )

x = 6

JK = (13 × 6) + 5 = 78 + 5 = 83

KL = (17 × 6) - 19 = 102 - 19 = 83

JL = (8 × 6) + 35 = 48 + 35 = 83

ΔJKL is equilateral with side = 83

4 0
3 years ago
Suppose that an object moves along the y-axis so that its location is y=x2+3x at time x. (Here y is in meters and x is in second
vfiekz [6]

Answer:

a) 13 m/s

b) (15  + h) m/s

c) 15 m/s

Step-by-step explanation:

if the location is

y=x²+3*x

then the average velocity from 3 to 7 is

Δy/Δx=[y(7)-y(3)]/(7-3)=[7²+3*7- (3²+3*3)]/4= 13 m/s

then the average velocity from x=6 to to x=6+h

Δy/Δx=[y(6+h)-y(6)]/(6+h-6)=[(6+h)²+3*(6+h)- (6²+3*6)]/h= (2*6*h+3*h+h²)/h=2*6+3= (15 + h) m/s

the instantaneous velocity can be found taking the limit of Δy/Δx when h→0. Then

when h→0 , limit Δy/Δx= (15 + h) m/s = 15 m/s

then v= 15 m/s

also can be found taking the derivative of y in x=6

v=dy/dx=2*x+3

for x=6

v=dy/dx=2*6+3 = 12+3=15 m/s

7 0
3 years ago
What IS 20 divided by 13 ?
goldenfox [79]

Solution,\mathrm{Convert\:improper\:fractions\:to\:mixed\:numbers}:\quad \frac{20}{13}=1\frac{7}{13}

Steps:

\frac{20}{13}

\mathrm{Long\:Division}\:\frac{20}{13}:\quad 1\quad \mathrm{Remainder}\quad \:7

Convert\:to\:mixed\:number:\:Quotient\frac{Remainder}{Divisor},\\\frac{20}{13}=1\frac{7}{13}

Hope\: This\: Helps!!!

4 0
3 years ago
Read 2 more answers
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