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choli [55]
3 years ago
6

Miguel has finished 39 out of 65 problems on a test. What percent of the total number of problems in the test Miguel finished? S

how work
Mathematics
1 answer:
vlada-n [284]3 years ago
5 0

Answer:

60%

Step-by-step explanation:

39/65 = 0.6

0.6 X 100 = 60% (Decimal to Percent)

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Circle C has radius of 10 cm. Each of points B and D is on the midpoint of the radius. Find the area of the shaded region.
olya-2409 [2.1K]
Simple :)
Area of shaded part = are of 1/4 circle - area of both triangles.
Are of circle = pie r^2 so 100x3.14 = 314 cm2.
Area of triangle AOB= area of triangleDOE = bh/2= 5x10/2= 25 each
However, the traingles share a common area which is quad DOB(I)
Lets take traingle AOE, whose are is bh/2=10x10/2=50cm2.
50-area of triangle A(I)E= 50-(
7 0
3 years ago
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Elsa went for a drive in her new car. She drove 345.6 miles at a speed of 54 miles per hour. For how many hours did she drive
Kitty [74]

Answer:

6.4

Step-by-step explanation:

You could use a calculator

Or....

Do 345.6/54 and get 6.4

6 0
3 years ago
Given that cos (x) = 1/3, find sin (90 - x)
ddd [48]

Answer:

\sin(90^{\circ} - x)=\frac{1}{3}

Step-by-step explanation:

Given: \cos (x)=\frac{1}{3}

We have to find the value of \sin(90^{\circ} - x)

Since Given \cos (x)=\frac{1}{3}

Using trigonometric identity,

\sin(90^{\circ} - \theta)=\cos\theta

Thus, for  \sin(90^{\circ} - x) comparing , we have,

\theta=x

We get,

\sin(90^{\circ} - x)=\cos x=\frac{1}{3}

Thus, \sin(90^{\circ} - x)=\frac{1}{3}

3 0
4 years ago
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Graph 2x-5y=1 <br> Help I don’t know how to do it
lapo4ka [179]

Answer:

Step-by-step explana

Move all terms that don't contain

x

to the right side and solve.

x

=

1

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5 0
3 years ago
Luke earned a grade of 88% on his multiple choice history final that had a total of
weqwewe [10]

Answer:

176

Step-by-step explanation:

88% = 88/100

88 × 2 = 176

176/200

4 0
3 years ago
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