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3 years ago

What is the volume of this pyramid?

Mathematics

2 answers:

Ipatiy [6.2K]3 years ago

8 0

Answer:

The volume of the pyramid is $2,520\ cm^{3}$

Step-by-step explanation:

we know that

The volume of a pyramid is equal to

$V=\frac{1}{3}Bh$

where

B is the area of the base of the pyramid

h is the height of the pyramid

Find the area of the base B

$B=\frac{1}{2}(18*24)=216\ cm^{2}$ ------> is the area of a triangle

Find the volume

$V=\frac{1}{3}(216)(35)=2,520\ cm^{3}$

Kaylis [27]3 years ago

3 0

The Volume of this pyramid is 5040 cm³
Hope this helps

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An octagonal swimming pool has a base area of 22 square feet The pool is 3 feet deep How many cubic feet of water can the pool h

LenKa [72]

The pool can hold 65.84 ft³ of water

<u>Explanation:</u>

Given:

Shape of pool = octagonal

Base area of the pool = 22 ft²

Depth of the pool = 3 feet

Volume, V = ?

We know:

Area of octagon = 2 ( 1 + √2) a²

22 ft² = 2 ( 1 + √2 ) a²

$\frac{11}{1+\sqrt{2} } = a^2$

a² = $\frac{11}{2.42}$

a² = 4.55

a = 2.132 ft

Side length of the octagon is 2.132 ft

We know:

Volume of octagon = $2(1+\sqrt{2} ) X (a)^2 X h$

$V = 2(1+\sqrt{2})X (2.132)^2 X 3\\ \\V = 2 ( 2.414) X 4.5454 X 3\\\\V = 65.84 ft^3$

Therefore, the pool can hold 65.84 ft³ of water

8 0

3 years ago

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FinnZ [79.3K]

9514 1404 393

Answer:

Step-by-step explanation:

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y = kx

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7 0

2 years ago

The school auditorium can hold at most 480 people. There were 185 advance tickets sold for the school play. Write and solve an i

attashe74 [19]

Answer:

p + 185 ≤ 480

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Step-by-step explanation:

3 0

2 years ago

Which expression is equivalent to (16 x Superscript 8 Baseline y Superscript negative 12 Baseline) Superscript one-half?.

loris [4]

To solve the problem we must know the Basic Rules of Exponentiation.

<h2>Basic Rules of Exponentiation</h2>

$x^ax^b = x^{(a+b)}$
$\dfrac{x^a}{x^b} = x^{(a-b)}$
$(a^a)^b =x^{(a\times b)}$
$(xy)^a = x^ay^a$

$x^{\frac{3}{4}} = \sqrt[4]{x^3}= (\sqrt[3]{x})^4$

The solution of the expression is $\dfrac{4x^4}{y^6}$ .

<h2>Explanation</h2>

Given to us

$(16x^8y^{12})^{\frac{1}{2}}$

Solution

We know that 16 can be reduced to $2^4$ ,

$=(2^4x^8y^{12})^{\frac{1}{2}}$

Using identity $(xy)^a = x^ay^a$ ,

$=(2^4)^{\frac{1}{2}}(x^8)^{\frac{1}{2}}(y^{12})^{\frac{1}{2}}$

Using identity $(a^a)^b =x^{(a\times b)}$ ,

$=(2^{4\times \frac{1}{2}})\ (x^{8\times\frac{1}{2}})\ (y^{12\times{\frac{1}{2}}})$

Solving further

$=2^2x^4y^{-6}$

Using identity $\dfrac{x^a}{x^b} = x^{(a-b)}$ ,

$=\dfrac{2^2x^4}{y^6}$

$=\dfrac{4x^4}{y^6}$

Hence, the solution of the expression is $\dfrac{4x^4}{y^6}$ .

Learn more about Exponentiation:

brainly.com/question/2193820

8 0

2 years ago

Given: x + 2y = -6.

wel

very positive about these results

4 0

2 years ago