<u>Let's consider the facts at hand</u>:
- By Vertical Angle Theorem ⇒ ∠BCE = ∠DCF
- ∠BEC = ∠DFC
- Sides BE = DF
<u>Based on the diagram, triangles BCE and triangles DCF are similar</u>
⇒ based on the Angle-Angle theorem
⇒ since ∠BCE = ∠DCF and ∠BEC = ∠DFC
⇒ the two triangles are similar
Hope that helps!
<em>Definitions of Theorem I used:</em>
- <u><em>Vertical Angle Theorem: </em></u><em>opposite angles of two intersecting lines must be equal</em>
- <u><em>Angle-Angle Theorem:</em></u><em> if two angles of both triangles are equal, then the given triangles must be similar</em>
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So, you already know that angle CBD is 68 degrees, and the complementary angle to angle CBD is angle CBA. These angles together make 180 degrees because segment DBA is a straight line consisting of angles CBD and CBA. 180-68(the angle you already know) is 112 degrees for angle CBA. Then you repeat this process to find the other angles
Figure A, the rectangle in the top left corner is the correct answer.
Answer:
T^75
Step-by-step explanation:
3 times 5 = 15
5 times 15 = 75
Answer: 8 vertices
Step-by-step explanation: A cube has 6 square faces. Each segment formed by the intersection of 2 faces is called an edge so a cube has 12 edges. Each point formed by the intersection of 3 edges is called a vertex so a cube has 8 vertices.