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3 years ago

HELP HELP HELP HELP HELP

Mathematics

1 answer:

vaieri [72.5K]3 years ago

8 0

9/5 you just do the cross multiply

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Suppose you just received a shipment of twelve televisions. Three of the televisions are defective. If two televisions are rando

qwelly [4]

Answer: The probability that both televisions work is 0.5625 .

The probability at least one of the two televisions does not work is 0.4375.

Step-by-step explanation:

Given : Number of televisions received in shipment= 12

Number of defective televisions received in shipment= 3

Then proportion of defective televisions = $\dfrac{3}{12}=0.25$

Using binomial probability formula, the probability of getting success in x trials is given by :-

$P(x)=^nC_xp^x(1-p)^{n-x}$

If two televisions are randomly selected, then the probability that both televisions work will be :-

$P(0)=^2C_0(0.25)^0(0.75)^2=(0.75)^2=0.5625$

The probability at least one of the two televisions does not work will be :-

$P(x\geq1)=1-P(0)=1-0.5625=0.4375$

6 0

2 years ago

4 2/7 ÷3 4/5= how do you answer this?

Pavel [41]

is it 42 or 4 and 2 separate

6 0

3 years ago

Which statements are true about the process for adding and subtracting the rational expressions? Check all that apply. The expre

Margarita [4]

It isn't true at all it isn't a question even

5 0

3 years ago

A card is drawn from a standard deck of 52 playing cards. If the card is a club, a fair coin is flipped 9 times and the number o

olasank [31]

Answer: There are 18 elements in the sample space for this experiment

Step-by-step explanation:

Total cards = 52

Total outcomes on tossing a coin = 2 [1 head , 1 tail]

If the card is a club, a fair coin is flipped 9 times and the number of heads flipped is noted (but card drawn is not noted)).

Possible outcomes for heads = 0,1,2,...,9

So sample space for this event = {0,1,2,3,4,5,6,7,8,9}   (Total 10 elements )  (i)

If it is not a club, the coin is only flipped 3 times, but this time the result of each flip is noted(but card drawn is not noted).

Sample space with all possible outcomes ={TTT,TTH, THT, HTT, HTH,HHT,THH,HHH} (Total 18 elements ) (ii)

From (i) and (ii), Total elements in the sample space for this experiment = 10+8 = 18

Hence, there are 18 elements in the sample space for this experiment

4 0

3 years ago

HELP 45 POINTS!! FIRST CORRECT ANSWER GETS BRAINLIEST

Alexandra [31]

Answer:

a. She needs to hang each triangle from its center of gravity or centroid, which is the point at which the three medians of the triangle intersect.

Step-by-step explanation:

Medians meet at a centroid of the triangle. The centroid is the triangle's center of gravity.

7 0

2 years ago