Question

Find the value of x in the isosceles triangle shown below.

Answer 1

Answer:

x = $\sqrt{26}$

Step-by-step explanation:

using pythagoras theorem

here $\sqrt{13}$ and $\sqrt{13}$ are the legs of the right angled triangle and x is hypotenuse.

a^2 + b^2 = c^2

$(\sqrt{ 13 })^2 + (\sqrt{13})^2 = x^2$

13 + 13 = x^2

26 = x^2

$\sqrt{26}$ = x

Answer 2

Answer:

answer would be c

Step-by-step explanation:

hope this helps