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aleksandr82 [10.1K]
3 years ago
9

A rectangular pool is 21 meters wide and 28 meters long. If you swim diagonally across the pool, how many meters would you be sw

imming?
Mathematics
1 answer:
babunello [35]3 years ago
6 0
To figure this out, you must use the Pythagorean theorem.
That is were you take the width of the opject, and square it (21 squared). and take the length of the object and square it (28 squared),
 then add those together. (21 squared + 28 squared) = NUMBER
then take that number that you got, and find the square root of it. (<span>√NUMBER)
and that's your answer.

So it would be: 35 meters</span>
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Step-by-step explanation:

j=25+5

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Let's review the options:
A. 169-26y+y^2 can be factorised into (13-y)(13-y)
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D. 25+10y+y^2 can be factorised into (5+y)(5+y)

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3 years ago
Newton's law of cooling states that the temperature of an object changes at a rate proportional to the difference between its te
Aleonysh [2.5K]

Answer:

t=5.18 minute

Step-by-step explanation:

Using Newton's law of cooling

\frac{dT}{dt}=-k(T-T_{s})

T is temperature of a cup of coffee at any time t T_{s}, is the temperature of the surrounding and k is a constant of proportionality in this negative because temperature is decreasing.

T(0)=190\\T(1)=170\\T_{s}=66

\frac{dT}{dt}=-k(T-T_{s})\\\frac{dT}{(T-T_{s})}=-k*dt\\\int\limits {\frac{1}{T-T_{s} } } \, dT=-\int\limits {k} \, dt\\ln(T-T_{s})=k*t+C\\e*ln(T-T_{s})=e^{k*t+C} \\T-T_{s}=e^{k*t}*e^{C}\\e^{C}=C\\T-T_{s}=e^{k*t}*C\\T=T_{s}+e^{k*t}*C

To find constant knowing the time and the temperature the first step of the change of energy in cup of coffee

T=T_{s} +e^{-k*t}*C\\ C=190-66=124\\170=66+124*e^{-k*2}\\ 170-66=124*e^{-k*2}\\ln(\frac{104}{124})=ln*e^{-k*2}\\-0.175=-k*2\\k=0.08794

Now using the constant of decreasing can find the time to be a 145 temperature the cup of coffee

145=66+124*e^{-k*t} \\145-66=124*^{-0.087*t}

ln(0.637)=ln*e(-0.087*t)\\-0.45=-0.087*t\\t=5.18minutes

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Answer:

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