Answer:
see below
Step-by-step explanation:
Your spreadsheet or graphing calculator can do this for you.
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If you want to do it by hand, pick a few values for x, compute the corresponding values of f(x), plot those points, and draw a smooth curve through them. You know the horizontal asymptote is y=0, and the whole graph is in the 3rd and 4th quadrants, since the exponential function has been reflected over the x-axis by the leading minus sign.
Answer:
B. y=3(x-1)2 + 3
Step-by-step explanation:
Given that
vertex of the parabola is at the point (1,3)
let's verify, if the option B is the correct equation of the parabola.
comparing to standard equationof parabola (standard quadratic equation), we get
to find the vertex we use formula for x- coordinate as
to find y put x=1 in the Eq1, we get
vertex =(x,y) = (1, 3)
thus vertex of the parabola from the equation y=3(x-1)2 + 3 is (1,3), thus verified