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Marina86 [1]
3 years ago
14

In a volcanic eruption, a 2400-kg boulder is thrown vertically upward into the air. At its highest point, it suddenly explodes i

nto two fragments, one being three times the mass of the other. The lighter fragment starts out with only horizontal velocity and lands 274 m directly north of the point of the explosion. Where will the fragment land? Neglect any air resistance.
Physics
1 answer:
crimeas [40]3 years ago
7 0

Answer:

91.33 m towards the south

Explanation:

At the highest point , the boulder will be at rest so its velocity will be zero . When it explodes into two fragments , momentum in horizontal direction will be conserved since there is no external force in horizontal direction . So

m₁ v₁ = m₂ v₂

m₁ v₁ = 3m₁ v₂

v₁ = 3 v₂

So velocity of larger fragment will be  1 / 3  times the velocity of smaller  one , in horizontal direction , to conserve momentum.

The smaller fragment  travels a distance of 274 m horizontally in the north , the larger fragment will travel 274 / 3 or 91.33 m towards the south. It is so because time of fall for both is same , Or they travel in horizontal direction during the same time.

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