Answer:
2.22m/s
Explanation:
Given parameters:
M1 = 60kg
M2 = 75kg
V1 = 0m/s
V2 = 4m/s
Unknown;
Velocity after collision = ?
Solution:
To solve this problem, we must understand that the momentum before and after collision of the bodies must be the same;
M1 V1 + M2 V2 = v(M1 + M2)
So;
60 x 0 + 75 x 4 = v (60 +75)
300 = 135v
v = 2.22m/s
In a real system of levers, wheel or pulleys, the AMA (actual mechanical advantage) is less than the IMA (ideal mechanical advantage) because of the presence of friction.
In fact, the IMA and the AMA of a machine are defined as the ratio between the output force (the load) and the input force (the effort):

however, the difference is that the IMA does not take into account the presence of frictions, while the AMA does. As a result, the output force in the AMA is less than the output force in the IMA (because some energy is dissipated due to friction), and the AMA is less than the IMA.
I have no idea what that is, but all of your answers right
Answer:
Explanation:
Acceleration is defined as the change in velocity per unit of time
Acceleration (a) = ΔV/t
V = Velocity t = time
ΔV = V₂ - V₁ t = 11s
V₁ = 44m/s
V₂ = 66m/s
ΔV = 66 - 44
= 22m/s
Acceleration (a) = 22/11
= 2m/s²
Displacement (d): Displacement equals the original velocity multiplied by time plus one half the acceleration multiplied by the square of time.
d = v₀ + 1/2*at²
v₀ = 44m/s
a = 2m/s
t = 11s
d = 44 + 1/2*(2 x 11²)
= 44 + 121
d = 165m
Answer:
Their efforts would be expressed in units of Joules per second
Explanation:
The unit of their efforts can be derived from the formula of power which is given by the product of mass, acceleration and distance (the product is energy with unit joules) divided by time taken to complete the task (unit is seconds)
Therefore, the unit of their efforts would be joules per second