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Ugo [173]
3 years ago
13

A 65 Kg roller-blade is accelerating at 5 m/s/s across the side walk. What force would be necessary for this acceleration to occ

ur?
Physics
1 answer:
Neporo4naja [7]3 years ago
3 0
Newton's second law states that the force applied to an object is equal to the product between the mass m of the object and its acceleration a:
F=ma
Using m=65 kg and a=5 m/s^2, we can find the value of the force applied to the roller-blade to obtain this acceleration:
F=(65 kg)(5 m/s^2)=325 N
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A ski gondola is connected to the top of a hill by a steel cable oflength 620 m and diameter 1.5 cm. As thegondola comes to the
klemol [59]

Answer:

Explanation:

Given

Length of cable L=620 m

Diameter of cable d=1.5 cm

time taken to return to original position T=14 s

time taken to cover distance L

t=\frac{T}{2}=7 s

velocity

v=\frac{L}{t}=\frac{620}{7}=88.57 m/s

(b)Relation between velocity of wave Tension is

v=\sqrt{\frac{T}{\mu }} , where \mu =mass per unit Length

T=v^2\cdot \mu

T=(88.57)^2\cdot \frac{m}{L}

T=(88.57)^2\cdot \frac{\rho AL}{L}

where \rho =density\ of\ steel =7850 kg/m^3

A=area\ of\ cross-section=\frac{\pi }{4}d^2=1.76\times 10^{-4} cm^2

T=(88.57)^2\cdot 7850\times 1.76\times 10^{-4}

T=10,883 N

5 0
3 years ago
An upward force is applied to a 6.0–kilogram box. This force displaces the box upward by 10.00 meters. What is the work done by
enyata [817]
We know that work= force x displacement along the direction of force
here force shoukd be equal to its self-weight.
thus, work= self-weight x displacement.
=mass x acceleration due to gravity x displacement.
= 6kg x 10m/s^2 x 10
60x10
=600J
7 0
4 years ago
Read 2 more answers
For trapezoid JKLM, A and B are midpoints of the legs. Find AB.
kodGreya [7K]

Answer:

AB = 29

Explanation:

For a better understanding, we must work this problem in a graphic way. In the attached image we can see the solution.

First, we draw a vertical dotted lines from the point J & K to the line ML, then we can see two new portions with the same length. Then with this simple analysis:

2x = 39 - 19

x = 10

Then we know that x = 10, another important data to find the answer is that the AB line is located in the midpoints of the legs. We also can see the right triangle MJ and the dotted line.

Now for every single right triangle, no matter its size and relationship between the vertical and the horizontal lengths, if some point is located in the hypotenuse (leg) at the middle of its length. This will be proportional to the vertical and the horizontal cathetus, therefore we will have the middle point on those two lines.

So, the AB line will be the sum of JK plus two times 5

AB = 19 + 5 + 5 = 29

7 0
3 years ago
What is the maximum value of the electric field in an electromagnetic wave whose average intensity is 4.50 w/m2 ?
Oksi-84 [34.3K]
Average intensity of electromagnetic wave is given by

I= (speed of light*permittivity*sq. electric field)/2

Speed of light = 3x10^8 m/s
Permittivity = 8.85x10^-12

Therefore,
Electric field = sqrt (2I/ (speed of light xpermittivity)) = sqrt ((2*4.50)/(3*10^8*8.85*10^-12)) = 58.22 V/m
7 0
3 years ago
Which of two factors influence the weight of an object due to gravitational pull?
Tresset [83]
The masses of the object and the planet it's on, and the distance between their centers.
7 0
3 years ago
Read 2 more answers
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