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Ugo [173]
3 years ago
13

A 65 Kg roller-blade is accelerating at 5 m/s/s across the side walk. What force would be necessary for this acceleration to occ

ur?
Physics
1 answer:
Neporo4naja [7]3 years ago
3 0
Newton's second law states that the force applied to an object is equal to the product between the mass m of the object and its acceleration a:
F=ma
Using m=65 kg and a=5 m/s^2, we can find the value of the force applied to the roller-blade to obtain this acceleration:
F=(65 kg)(5 m/s^2)=325 N
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A certain organ pipe, open at both ends, produces a fundamental frequency of 288 Hz in air. Part A If the pipe is filled with he
alina1380 [7]

Answer:

773.25 Hz

Explanation:

Concept : In an open organ pipe in fundamental mode of vibration

wave length of wave λ = 2L

where L  is length of  the pipe

frequency   = velocity of sound / λ

Given values: fundamental frequency = 288 Hz

fluid is air. velocity of sound = 340 m/s

⇒ 288 = 340/2L

⇒L = 59.02 cm

The point to be noted is if the pipe is filled with helium initially at the same temperature, there would be change in the sound velocity .Then,  frequency of note produced will also be changed .

We know that velocity of sound is inversely proportional to  square root of molar mass of gas

velocity of sound in air / velocity of sound in helium = Square root of (Molar mass of Helium/ molar mass of air)

\frac{V_a}{V_{He}} = \sqrt{\frac{4}{28.8} } \\\frac{340}{V_{He}} =0.3725\\V_{He} =912.5 m/s

Now, frequency  = velocity of sound / λ

= 912.75 / (2 x 0.5902)

= 773.25 Hz

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3 years ago
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Answer:

B AND D

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6 0
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4 years ago
Which electron transition produces light of the highest frequency in the hydrogen atom?
allsm [11]

Answer:

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Explanation:

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3 years ago
Which of the the following distance vs time graphs represents an object the is moving at constant non zero velocity
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