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valina [46]
3 years ago
15

Think about your displacement at three different times throughout your day and compare it with e distance you traveled. (6 point

s)
Physics
1 answer:
photoshop1234 [79]3 years ago
5 0

Here, we are asked to calculate the total distance and displacement for three different times.

Before solving the question, first we have to understand the distance and displacement.

Displacement is the minimum distance travelled between two points. Hence, it is a vector quantity. On the other hand, the distance travelled is a scalar quantity.

The total displacement will be calculated by vector addition while total distance will follow algebraic addition.

Let us consider Ram travelled 3 km towards north from his home to office in 1 hour. The highway is straight. He reached at his office and saw that his office was closed. So, he came back. He stopped at shop for 2 minutes which was 2 km away from his office. Then he started his journey and reached him home.

Let his first distance travelled from home to office is s_{1} =\ 3\ km

Here, the displacement is also the same in magnitude with distance travelled and it is directed towards north.

The distance travelled by Ram from office to the shop s_{2} =2\ km

Here, the displacement is 2 km towards south.

The distance travelled by Ram from the shop to the office s_{3} =\ 1 \ k m

Here, the displacement is 1 km towards south.

Here, the total distance travelled  [s]\ =\ s_{1} +s_{2} +s_{3}

                                                                =3\ km+2\ km+1\ km

                                                                =6\ km

Now we have to calculate the total displacement. Here, the total displacement is zero.

It is because the initial and final points of his journey is same.

                             

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A pitcher throws an overhand fastball from an approximate height of 2.65 m and at an angle of 2.5° below horizontal. The catcher
rodikova [14]

Answer:

The initial velocity of the pitch is approximately 36.5 m/s

Explanation:

The given parameters of the thrown fastball are;

The height at which the pitcher throws the fastball, h₁ = 2.65 m

The angle direction in which the ball is thrown, θ = 2.5° below the horizontal

The height above the ground the catcher catches the ball, h₂ = 1.02 m

The distance between the pitcher's mound and the home plate = 18.5 m

Let 'u' represent the initial velocity of the pitch

From h = u_y·t + 1/2·g·t², we have;

u_y = The vertical velocity = u·sin(θ) = u·sin(2.5°)

h = 2.65 m - 1.02 m = 1.63 m

uₓ·t = u·cos(θ) = u·cos(2.5°) × t = 18.5 m

∴ t = 18.5 m/(u·cos(2.5°))

∴ h = u_y·t + 1/2·g·t² =  (u·sin(2.5°))×(18.5/(u·cos(2.5°))) + 1/2·g·t²

1.63 = 8.5·tan(2.5°) + 1/2 × 9.8 × t²

t² = (1.63 - 8.5·tan(2.5°))/(1/2 × 9.8) = 0.25691469087

t = √(0.25691469087) ≈ 0.50686752763

t ≈ 0.50686752763 seconds

u = 18.5 m/(t·cos(2.5°)) = 18.5 m/(0.50686752763 s × cos(2.5°)) = 36.5334603 m/s ≈ 36.5 m/s

The initial velocity of the pitch = u ≈ 36.5 m/s.

3 0
3 years ago
Three resistors having resistances of LaTeX: 4.0\;\Omega4.0 Ω, LaTeX: 6.0\;\Omega6.0 Ω, and LaTeX: 10.0\;\Omega10.0 Ω are connec
aalyn [17]

Answer:

Explanation:

Given that three resistor of resistance

R1 = 4 Ω

R2 = 6 Ω

R3 = 10 Ω

The resistor are connected in parallel, the equivalent resistance is

1 / Req = 1 / R1 + 1 / R2 + 1 / R3

Rearranging this we have

Req = R1•R2•R3 / (R2•R3 + R1•R3 + R1•R2)

Req = 4 × 6 × 10 / (6×10 + 4 × 10 + 4 × 6)

Req = 240 / (60 + 40 + 24)

Req = 240 / 124

Req = 1.94 Ω

The parallel connection is connected in series with a battery and a resistor.

Resistor resistance is

r = 2 Ω

Supply voltage of the battery is 12V

V = 12V

Let find the current flowing in the circuit.

V = I(Req + r)

I = V / (Req + r)

I = 12 / (1.94 + 2)

I = 12 / 3.94

I = 3.05A

So, this is the current flowing in the circuit and It is the same current that will be shared by the parallel resistance.

We can calculated the voltage across the parallel resistance

From ohms las

V = iR

V = I × Req

V = 3.05 × 1.94

V = 5.92 V.

Then, this the voltage across each parallel resistor.

Then, to know the current in the 10ohms resistance

V = iR

I = V / R3.

I = 5.92 / 10

I = 0.592 A.

The current in the 10 ohms resistor is 0.59A

5 0
3 years ago
What is the name of the variable that you can change in an experiment?
Schach [20]
That would be the independent variable.

Dependent variable changes according to the independent variable

I honestly don’t know about graphing and stable variables never heard of it before
7 0
3 years ago
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If an object is moving to the right and there is a net force acting on it to the left, what will happen to the object?
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3 years ago
The 17 foot ladder leans against a wall from a point that 3.3 feet away from the wall on the ground. What is the angle between t
Inessa05 [86]

Answer:

11.2°

Explanation:

Using the trigonometry ratio,

Note: Assuming the ladder, the wall and the horizontal forms a right angle triangle.

Cosθ = Opposite/Hypotenuse

SinΦ = O/H.......................... Equation 1

Where Φ = angle between the ladder and the wall, O = opposite, H =Hypotenuse.

make Ф the subject of the equation,

Ф = sin⁻¹(O/H).................. Equation 2

Given: O = 3.3 foot, H = 17 foot

Ф = sin⁻¹(3.3/17)

Ф = sin⁻¹(0.194/

Ф = 11.19°.

Ф = 11.2° ( to the nearest tenth degree)

Hence the ladder and the wall makes an angle of 11.2°

7 0
3 years ago
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