Question

A particle moving uniformly along the x axis is located at 16.6 m at 0.802 s and at 3.22 m at 2.71 s. Find its displacement. Answer in units of m

Answer 1

Displacement is a vector quantity, it is the difference between final and initial position of a particle.

Since particle initial position is 16.6 m and final position is 3.22 m.

Therefore,

$Displacement = final\ position -initial\ position=3.22 m-16.6 m\\\\=-13.38\ m$.

Thus, the displacement of the particle is 13.38 m in negative x- direction.