Yes, BUt where's the fraction
Answer:
0.35
Step-by-step explanation:
<h3>
<u>Answer</u><u>:</u><u>-</u></h3>
192 cm²
<h3>
<u>Step</u><u> </u><u>by</u><u> step</u><u> explanation</u><u> </u><u>:</u><u>-</u></h3>
Let us take the height be x , then its side = x + 4. Now half of base will be 12 cm .
<u>According</u><u> to Pythagoras Theorem :- </u>
=> base² + perpendicular ² = hypontenuse ²
=> 12² + x² = (x+4)²
=> 144 + x² = x² + 16 + 8x
=> 8x = 144-16
=> 8x = 128
=> x = 128/8
=> x = 16 cm .
Hence the height of ∆ is 16 cm .So the area will be half the product of base and altitude.
= 1/2 * 16 cm * 24cm .
= 192 cm²
<h3>
<u>★</u><u> </u><u>Hence</u><u> </u><u>the</u><u> </u><u>area</u><u> </u><u>of</u><u> </u><u>the </u><u>tria</u><u>ngle</u><u> is</u><u> </u><u>1</u><u>9</u><u>2</u><u> </u><u>cm²</u><u> </u><u>.</u></h3>
Answer:
B.
Step-by-step explanation:
So we know right off the bat the angles ABE and CBD are congruent because of vertical angles.
Now we can look at the sides.
The ratio for 27:18 = 3:2
The ratio for 36:24 = 3:2
They check out.
That means that the answer is B. SAS
Answer:
The answer is below
Step-by-step explanation:
The question is not complete, but I would show you how to solve it.
Solution:
A circle is the locus of a point such that its distance from a fixed point which is its center is always constant.
The tire has the shape of a circle. Therefore the distance the tire covers if it is pushed around once is the same as the circumference of the tire. The circumference is given by:
Circumference = 2πr; where r is the radius of the tire
Let us assume that the tire has a radius of 7 cm. Hence:
Circumference = 2π(7) = 44 cm
If the tire moves around 5 times, the distance covered = 5 * circumference of tire = 5 * 44 cm = 220 cm