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yarga [219]
3 years ago
8

K over 1.5 =3 what is the value of k

Mathematics
2 answers:
slega [8]3 years ago
7 0
I think it’s 4.5 not 100% sure tho
Makovka662 [10]3 years ago
5 0
4.5 is equal to k. This is the answer .
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I need help to these questions. Convert these fractions to a decimal 7/8 , 4 3/8. Thanks
ehidna [41]
Simple...

you have: \frac{7}{8} and 4 \frac{3}{8}

Now, the first one is easy just divide it...

\frac{7}{8} =0.875

Now....

4 \frac{3}{8}    needs to be converted...

Multiply the whole number*denominator...

4*8=32

Now add the numerator....

32+3=35

Now use the original denominator...

\frac{35}{8}

Now divide...

\frac{35}{8}=4.375


Thus, your answer.
7 0
2 years ago
Read 2 more answers
I'll give brainliest to correct answer TvT
laila [671]
It’s 1.4 bc 2.9-1.5
7 0
2 years ago
Read 2 more answers
Use the distributive property to simplify 5(w + 6) =
natulia [17]

Answer:

5w+30

5(w+6)=

5*w= 5w

5*6= 30

3 0
2 years ago
How do you solve the problem and what is the answer?<br><br>-2 = g -9<br>​
pogonyaev

Answer:

Hey Dude ok so it's g = 7 Have a nice day!

Step-by-step explanation:Simplifying

-2 = g + -9

Reorder the terms:

-2 = -9 + g

Solving

-2 = -9 + g

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Add '-1g' to each side of the equation.

-2 + -1g = -9 + g + -1g

Combine like terms: g + -1g = 0

-2 + -1g = -9 + 0

-2 + -1g = -9

Add '2' to each side of the equation.

-2 + 2 + -1g = -9 + 2

Combine like terms: -2 + 2 = 0

0 + -1g = -9 + 2

-1g = -9 + 2

Combine like terms: -9 + 2 = -7

-1g = -7

Divide each side by '-1'.

g = 7

Simplifying

g = 7

6 0
3 years ago
Read 2 more answers
The set of points (-3, 4), (-1, 1), (-3,-2), and (-5,1) identifies the vertices of a quadrilateral. Which is the most specific d
KIM [24]

Answer:

Option (4). Rhombus

Step-by-step explanation:

From the figure attached,

Distance AB = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

                     = \sqrt{(1-4)^2+(-5+3)^2}

                     = \sqrt{(-3)^2+(-2)^2}

                     = \sqrt{13}

Distance BC = \sqrt{(4-1)^2+(-3+1)^2}

                     = \sqrt{9+4}

                     = \sqrt{13}

Distance CD = \sqrt{(-2-1)^2+(-3+1)^2}

                     = \sqrt{9+4}

                     = \sqrt{13}

Distance AD = \sqrt{(1+2)^2+(-5+3)^2}

                     = \sqrt{9+4}

                     = \sqrt{13}

Slope of AB (m_{1}) = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

                           = \frac{4-1}{-3+5}

                           = \frac{3}{2}

Slope of BC (m_{2}) = \frac{4-1}{-3+1}

                            = -\frac{3}{2}

If AB and BC are perpendicular then,

m_{1}\times m_{2}=-1

But it's not true.

[m_{1}\times m_{2}=(\frac{3}{2})(-\frac{3}{2}) = -\frac{9}{4}]

It shows that the consecutive sides of the quadrilateral are not perpendicular.

Therefore, ABCD is neither square nor a rectangle.

Slope of diagonal BD = \frac{4+2}{-3+3}

                                    = Not defined (parallel to y-axis)

Slope of diagonal AC = \frac{1-1}{-1+5}

                                    = 0 [parallel to x-axis]

Therefore, both the diagonals AC and BD will be perpendicular.

And the quadrilateral formed by the given points will be a rhombus.

5 0
3 years ago
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