Answer:
227.43
Step-by-step explanation:
You times 9 by 25.75 to get your answer
Answer:
28
Step-by-step explanation:
Let first integer = x
so second integer = x + 1
according to question we get the equation,,,,
(x) + (x + 1) < 55
x + x + 1 < 55
2x + 1 < 55
subtract 1 from both sides ,we get
2x < 54
divide both sides by 2 we get ......
x < 27
1st integer = x and x < 27
also as we need sum of integer with greates sum so we take x = 26
and 2nd integer = x+1
= 27 + 1
= 28
now if you add both the integers you get sum = 54 which is less than 55 and so this verify you second condtion also .......
hope this will help you
Please feel free to revert back for any further queries.
So basically we can check them all by multiplying all of the dimensions.
A: 3 * 3 * 40 = 360, so yes, it could be the dimensions
B: 4 * 4 * 20 = 320, so no, it couldn't be the dimensions
C: 6 * 6 * 10 = 360, so yes, it could be the dimensions.
D: 2.5 * 12 * 12 = 360, so yes, it could be the dimensions.
E: 3.6 * 10 * 10 = 360, so yes, it could be the dimensions.
I hope this helped :)
Simplify:
A(n) = -6 + (n - 1)(6) = -6 + (n)(6) + (-1)(6) = -6 + 6n - 6 = 6n - 12
Put n = 1, n = 4 and n = 10 to the expression:
A(1) = 6(1) - 12 = 6 - 12 = -6
A(4) = 6(4) - 12 = 24 - 12 = 12
A(10) = 6(10) - 12 = 60 - 12 = 48
<h3>Answer:</h3><h3>first term = -6, fourth term = 12 and tenth term = 48.</h3><h3>-6, 12, 48</h3>
<span>The answer to your question is a≥<span><span>9<span> or </span></span>a</span></span>≤<span>2</span>
