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Reptile [31]
4 years ago
9

A 75 lb weight hangs from a string as shown in the figure. Find the tensions T1 and T2 in the string.

Physics
1 answer:
fomenos4 years ago
4 0
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

Below is the solution:

<span>T2cos(30) - T1cos(50) = 0
</span><span>T1sin(50) + T2sin(30) - (75 lbs.)*(accel. grav.) = 0
</span><span>T2cos(30) - T1cos(50) = 0 --> T1 = T2cos(30)/cos(50)
</span>
<span>T1sin(50) + T2sin(30) - (75 lbs.)*(accel. grav.) = 0
</span>(<span>T2cos(30)/cos(50))sin(50) + T2sin(30) - (75 lbs.)*(accel. grav.) = 0 --> Solve for T2

</span><span>T1 = -T1cos(50)i + T1sin(50)j
T2 = T2cos(30)i + T2sin(3)j
</span>
<span>(T2cos(30)/cos(50))sin(50) + T2sin(30) - (75 lbs.)*(accel. grav.) = 0 --> T2[(cos(30)/cos(50))sin(50) + sin(30)] = 75*(grav) --> T2 = 75*grav/ [(cos(30)/cos(50))sin(50) + sin(30)]
</span>
<span> T2 = 1566.49 </span>
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HELP!!
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Answer:

Total displacement 155 m

Explanation:

From the question, the formula to apply will be that of cosine rule where:

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Substituting values in the equation as;

c=\sqrt{43^2+130^2-2*43*130*cos118}

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