Answer:
centimeters
Explanation:
earth's plates move only a few centimeters per year.
The car's average <em>speed</em> is 97 km/hr.
Then for calculation purposes, we can assume that it covers 97 km in the
first hour, 97 km in the second hour, 97 km in the third hour, and 97 km in
the fourth hour.
All together, the car covers (97 x 4) = <em>388 km</em> of distance.
We don't know the car's velocity, because we have no information about the
<em>direction</em> it moved at any time during the four hours. So we have no way to
calculate how far it was from the starting point at the end of the fourth hour.
For all we can tell, if the direction (and therefore the velocity) varied just right,
the car could have ended up exactly where it started.
Answer:
dₓ = 1.35 m
dy = 1.86 m
Explanation:
In order to find the vertical and horizontal components of the displacement, we can assume a right triangle. Such that, the length of string is the hypotenuse, making and angle of 54° with the base of triangle. The base is the horizontal component of displacement. And the perpendicular is the vertical component of displacement. Therefore:

where,
dₓ = horizontal component of displacement = ?
d = resultant displacement = 2.3 m
θ = angle between displacement and ground = 54°
Therefore,

<u>dₓ = 1.35 m</u>
For vertical component of displacement:

<u>dy = 1.86 m</u>
Answer:
The phase change of
can be theoretically understood as follows:
For transmission or propagation of waves between media the wave motion should maintain a principle of continuity meaning that the wave function at the interface should be continuous and diffrentiable at the interface.
At the point of incidence there are 2 types of waves reflected wave and the incident wave. Now the principle of continuity dictates that the sum of the phases of the above 2 waves should be same as that of transmitted wave. If we use these relations we notice that the reflected wave shall either change it's phase by
or will not change it's phase depending on the relationship between the refractive indices of the incident and the reflecting medium. For a solid boundary a phase change of
occurs.
We are given
V = 100 V
R = 500 Ω
C = 10^4 F
q(0) = 0
We are asked to find the charge q(t) of the RC capacitor.
To solve this, we use the formula:
q(t) = CV [1 - e^(-t/RC) ]
Substituting thet given values
q(t) = 10^4 (100) [1 - e^(-t/500(10^4) ]
q(t) = 1 x 20^6 [1 - e^(-2x10^7 t) ]
Since we only asked to get the charge q(t) in terms of t, the answer is
q(t) = 1 x 20^6 [1 - e^(-2x10^7 t) ]