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3 years ago

Newton established his three laws of motion to do what?

1 answer:

5 0

Newton established his three laws of motion to understand the motion of objects in a systematic way [ same thing as all Scientists did for human's curiosity ].

His three laws of motion are as follows:

First Law: - An object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.

Second Law: - The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.

Third Law: - For every action, there is an equal and opposite reaction

Hope this helps!

You might be interested in

If the mass of the ladder is 12.0 kgkg, the mass of the painter is 55.0 kgkg, and the ladder begins to slip at its base when her

Marysya12 [62]

Answer:

μ = 0.336

Explanation:

We will work on this exercise with the expressions of transactional and rotational equilibrium.

Let's start with rotational balance, for this we set a reference system at the top of the ladder, where it touches the wall and we will assign as positive the anti-clockwise direction of rotation

fr L sin θ - W L / 2 cos θ - W_painter 0.3 L cos θ = 0

fr sin θ - cos θ (W / 2 + 0,3 W_painter) = 0

fr = cotan θ (W / 2 + 0,3 W_painter)

Now let's write the equilibrium translation equation

X axis

F1 - fr = 0

F1 = fr

the friction force has the expression

fr = μ N

Y Axis

N - W - W_painter = 0

N = W + W_painter

we substitute

fr = μ (W + W_painter)

we substitute in the endowment equilibrium equation

μ (W + W_painter) = cotan θ (W / 2 + 0,3 W_painter)

μ = cotan θ (W / 2 + 0,3 W_painter) / (W + W_painter)

we substitute the values they give

μ = cotan θ (12/2 + 0.3 55) / (12 + 55)

μ = cotan θ (22.5 / 67)

μ = cotan tea (0.336)

To finish the problem, we must indicate the angle of the staircase or catcher data to find the angle, if we assume that the angle is tea = 45

cotan 45 = 1 / tan 45 = 1

the result is

μ = 0.336

5 0

4 years ago

If the area of a concrete slap weighing 300n is 400cm2 ,how much pressure can it apply when kept on the ground

aleksklad [387]

Answer:

7500 N/m²

Explanation:

From the question given above, the following data were obtained:

Force (F) = 300 N

Area (A) = 400 cm²

Pressure (P) =?

Next, we shall convert 400 cm² to m². This can be obtained as follow:

1×10⁴ cm² = 1 m²

Therefore,

400 cm² = 400 cm² × 1 m² / 1×10⁴ cm²

400 cm² = 0.04 m²

Finally, we shall determine the pressure. This can be obtained as follow:

Force (F) = 300 N

Area (A) = 0.04 m²

Pressure (P) =?

P = F/A

P = 300 / 0.04

P = 7500 N/m²

3 0

3 years ago

Short essay your teacher have provided you

Zinaida [17]

I don’t understand....?

6 0

3 years ago

A skater of mass 40 kg is carrying a box of mass 5 kg. The skater has a speed of 5 m/s with respect to the floor and is gliding

Yuki888 [10]

For the part a) we need only the momentum of the box and we have the data to find it.

Momentum is given by,

$p=mv$

where clearly, p is the momentum, m the mass of the box and v is the velocity.

Substituting,

$p=(5kg)(5m/s)\\p=25kg.m/s$

For part b) we need an analysis of the situation. We understand that the box on a surface that has no friction will continue to rotate at the same speed previously defined. The box can only stop with friction, so,

$p=(5kg)(5m/s)\\p=25kg.m/s$

It is the same that part a)

8 0

3 years ago

Calculate the momentum, A bald eagle with a mass of 26.4 kg and velocity of 15.6 m/s

AveGali [126]

Answer:

411.84 kg m/s

Explanation:

Formula :

Momentum = mass × velocity

=========================================================

Given :

⇒ mass = 26.4 kg

⇒ velocity = 15.6 m/s

=========================================================

Solving :

⇒ Momentum = 26.4 × 15.6

⇒ Momentum = 411.84 kg m/s

3 0

2 years ago