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Amanda [17]
3 years ago
12

The pressure and volume of a fixed mass of gas _ are related. if one decreases, the other ___ ___ this relationship is known as

___ ___ law. the volume of a fixed ___ ___ of a gas is directly proportional to its ___ ___ temperature. this relationship is known as ___ ___ law. ___ ___ law states that the pressure of a gas is ___ ___ proportional to the kelvin temperature if the volume remains constant. these three separate gas laws can be written as a single expression called the ___ ___ gas law. it can be used in situations in which only the ___ ___ of gas is constant.
Physics
1 answer:
mihalych1998 [28]3 years ago
5 0
1) Inversely
2) increases
3) Boyle's
4) mass
5) Kelvin
6) Charles's
7) Gay-Lussac's
8) directly
9) combined
10) the amount

<span>The pressure and volume of a fixed mass of gas are inversely related. If one decreases, the other increases. This relationship is known as Boyle's law. The volume of a fixed mass of a gas is directly proportional to its kelvin temperature. This relationship is known as Charles's law. Gay-Lussac's law states that the pressure of a gas is directly proportional to the kelvin temperature if the volume remains constant. These three separate gas laws can be written as a single expression called the combined gas law. It can be used in situations in which only the amount of gas is constant. </span>

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Un cuerpo se mueve, partiendo del reposo, con una aceleración constante de 8 m/s². Calcular la velocidad que tiene al cabo de 5s
nataly862011 [7]

Answer:

v = 40 m / s

Explanation:

Let's use the expressions for accelerated motion

         v = v₀ + a t

where vo is the initial velocity, at the acceleration and t is the time.

as the body starts from rest its initial velocity is zero

         v = 0 + at

let's calculate

         v = 8  5

         v = 40 m / s

8 0
2 years ago
A rock, with a density of 3.55 g/cm^3 and a volume of 470 cm^3, is thrown in a lake. a) What is the weight of the rock out of th
SIZIF [17.4K]

Answer:

a) Weight of the rock out of the water = 16.37 N

b) Buoyancy force = 4.61 N

c) Mass of the water displaced = 0.47 kg

d) Weight of rock under water = 11.76 N

Explanation:

a) Mass of the rock out of the water = Volume x Density

   Volume = 470 cm³

   Density = 3.55 g/cm³

   Mass = 470 x 3.55 = 1668.5 g = 1.6685 kg

   Weight of the rock out of the water = 1.6685 x 9.81 = 16.37 N

b) Buoyancy force = Volume x Density of liquid x Acceleration due to gravity.

   Volume = 470 cm³

   Density of liquid = 1 g/cm³

   \texttt{Buoyancy force}= \frac{470\times 1\times 9.81}{1000} = 4.61 N

c) Mass of the water displaced = Volume of body x Density of liquid

   Mass of the water displaced = 470 x 1 = 470 g = 0.47 kg

d) Weight of rock under water = Weight of the rock out of the water - Buoyancy force

   Weight of rock under water = 16.37 - 4.61  =11.76 N

3 0
3 years ago
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Gnom [1K]

Answer:

So mass of the object will be 3.2 kg

Explanation:

We have net force on the object F = 16 N

Acceleration of the object a=5m/sec^2

We have top find the mass of the object

From newton law of motion we know that force is given by

F = ma , here m is mass and a is acceleration

So 16=5\times m

m=3.2kg

So mass of the object will be 3.2 kg

3 0
3 years ago
The weight of a body kept at a distance of 6400 km from the centre of the
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Answer:

2.5N

Explanation:

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so the weight will be reduced to 1/4 of 10N

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Answer:

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