<h2>your answer is going to be image 1 that one looks the most decent </h2>
        
                    
             
        
        
        
Answer:
Explanation:
Block A sits on block B and force is applied on block A . Block A will experience two forces 1) force P and 2 )  friction force in opposite direction of motion . Block B will experience one force that is force of friction in the direction of motion . 
Let force on block A be P . friction force on it will be equal to kinetic friction, that is μ mg , where μ is coefficient of friction and m is mass of block A 
friction force = .4 x 2.5 x 9.8 
= 9.8 N 
net force on block A = P - 9.8 
acceleration = ( P - 9.8 ) / 2.5 
force on block B = 9.8 
acceleration = force / mass 
= 9.8 / 6 
for common acceleration 
 ( P - 9.8 ) / 2.5  = 9.8 / 6
( P - 9.8 ) / 2.5 = 1.63333
P = 13.88 N . 
 
        
             
        
        
        
Answer:
 the formulae is f = mg = vpg
 
        
             
        
        
        
The density of silver is ρ = 10500 kg/m³ approximately.
Given:
m = 1.70 kg, the mass of silver
t = 3.0 x 10⁻⁷ m, the thickness of the sheet
Let A be the area.
Then, by definition,
m = (t*A)*ρ
Therefore
A = m/(t*ρ)
    = (1.7 kg)/ [(3.0 x 10⁻⁷ m)*(10500 kg/m³)]
    = 539.7 m²
Answer: 539.7 m²