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IgorLugansk [536]
3 years ago
7

Which sets of side lengths could form a triangle? Choose all that apply.

Mathematics
1 answer:
svlad2 [7]3 years ago
4 0
What are the answer choices
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What 5+5=10 5+23#qrka
jolli1 [7]
5+23= 28 .........................
4 0
3 years ago
Read 2 more answers
3. Using techniques from Calculus, show directly that the maximum value of a 1-D Gaussian distribution occurs at the point x = μ
Vilka [71]

Answer:

For a scaler variable, the Gaussian distribution has a probability density function of

p(x |µ, σ² ) = N(x; µ, σ² ) = 1 / 2π×e^{\frac{-(x-u)^{2}}{2s^{2} }  }

The term will have a maximum value at the top of the slope of the 1-D Gaussian distribution curve that is when exp(0) =1 or when x = µ

Step-by-step explanation:

Gaussian distributions have similar shape, with the mean controlling the location and the variance controls the dispersion  

From the graph of the probability distribution function it is seen that the the peak is the point at which the slope = 0, where µ = 0 and σ² = 1 then solution for the peak = exponential function = 0 or x = µ

5 0
3 years ago
6r-16<br> _<br> r r=4<br> What is the answer?
Setler [38]
The answer is 8 
6(4)-16=8  :)

3 0
3 years ago
Write an equation for the quotient of a number and -12
ivanzaharov [21]
Quotient Rule. Objectives: In this tutorial, we derive the formula for finding the derivative of a quotient of two functions and apply this formula to several examples. After working through these materials, the student should be able to derive the quotient rule and apply it.
Visual
5 0
3 years ago
Which point is a solution to the system of inequalities below?
vodomira [7]

The ordered pair which is a solution to the given inequality is: C. (2, 1).

<h3>What is an inequality?</h3>

An inequality can be defined as a mathematical relation that compares two (2) or more integers and variables in an equation based on any of the following arguments:

  • Less than (<).
  • Greater than (>).
  • Less than or equal to (≤).
  • Greater than or equal to (≥).

Next, we would test the ordered pair with the given inequality to determine a solution as follows:

For ordered pair (4, 4), we have:

3x + 2y < 15

3(4) + 2(4) < 15

12 + 8 < 15

20 < 15 (False).

For ordered pair (3, 3), we have:

3x + 2y < 15

3(3) + 2(3) < 15

9 + 6 < 15

15 < 15 (False).

7x - 4y > 9

7(3) - 4(3) > 9

21 - 12 > 9

9 > 9 (False)

For ordered pair (2, 1), we have:

3x + 2y < 15

3(2) + 2(1) < 15

6 + 2 < 15

8 < 15 (True).

7x - 4y > 9

7(2) - 4(1) > 9

14 - 4 > 9

10 > 9 (True)

For ordered pair (1, 0), we have:

3x + 2y < 15

3(1) + 2(0) < 15

3 + 0 < 15

3 < 15 (True).

7x - 4y > 9

7(1) - 4(0) > 9

7 - 4 > 9

3 > 9 (False)

Read more on inequality here: brainly.com/question/27166555

#SPJ1

7 0
1 year ago
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