The moments to the left of the pivot must be equal to the moments on the right. Let d represent the distance of each mass from the pivot, which is at the 50 cm mark.
md₁ + md₂ = md₃ + md₄
m cancels out from both sides,
d₁ + d₂ - d₃ = d₄
(50 - 27) + (50 - 38) - (99 - 50) = d₄
d₄ = -14
That means the mass should be placed 14 cm to the left of the pivot, at the 36 cm mark.
Neptune is the farthest front the sun.
Answer:
A High-to-Low
Explanation:
its like water running down a hill.
Only the horizontal component of the tension force is performing work on the crate. This component has magnitude (50 N) cos(30°) = 25√3 N, so the work done is
(25√3 N) (10 m) = 250√3 N•m ≈ 433 J
So in your question where ask to find the dipole moment of HI in C.M. So in my calculation by converting the given data from Debyes to Coulomb Meteres is that 1 Dyebes is equals to 3.33X10^(-30) C.M and the answer would be 1.40X10(-30)C.M. I hope you are satisfied with my answer and feel free to ask for more