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marshall27 [118]
3 years ago
8

Which is located furthest from our sun?

Physics
2 answers:
eimsori [14]3 years ago
4 0
Neptune is the farthest front the sun.
marishachu [46]3 years ago
3 0

Answer:

c

Explanation:

others stars are locared furthest from the sun

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A 75 lb weight hangs from a string as shown in the figure. Find the tensions T1 and T2 in the string.
fomenos
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

Below is the solution:

<span>T2cos(30) - T1cos(50) = 0
</span><span>T1sin(50) + T2sin(30) - (75 lbs.)*(accel. grav.) = 0
</span><span>T2cos(30) - T1cos(50) = 0 --> T1 = T2cos(30)/cos(50)
</span>
<span>T1sin(50) + T2sin(30) - (75 lbs.)*(accel. grav.) = 0
</span>(<span>T2cos(30)/cos(50))sin(50) + T2sin(30) - (75 lbs.)*(accel. grav.) = 0 --> Solve for T2

</span><span>T1 = -T1cos(50)i + T1sin(50)j
T2 = T2cos(30)i + T2sin(3)j
</span>
<span>(T2cos(30)/cos(50))sin(50) + T2sin(30) - (75 lbs.)*(accel. grav.) = 0 --> T2[(cos(30)/cos(50))sin(50) + sin(30)] = 75*(grav) --> T2 = 75*grav/ [(cos(30)/cos(50))sin(50) + sin(30)]
</span>
<span> T2 = 1566.49 </span>
4 0
4 years ago
Assume each tick mark represents 1 cm. Calculate the total displacement if a toy car starts at 0, moves 5 cm to the left, then 8
borishaifa [10]
<h2>Answer:</h2>

Total displacement is zero cm

<h2>Explanation:</h2>

Look at the picture

8 0
3 years ago
Read 2 more answers
A sound wave in a steel rail has a frequency of 620 hz and a wavelength of 10.5m. What is the speed of sound in steel?
madam [21]
Speed = frequency x wavelength
speed = 620 x 10.5 = ..... m/s
7 0
3 years ago
Aluminium has a specific heat capacity of 900 J/(kg°C).
Ivanshal [37]

Answer:

24300000K

Explanation:

Q=mc(change in temperature)

900X2.0=1800.0

1800.0X13500= 24300K

4 0
3 years ago
Give two mathematical examples of Newton's third law and how you get the solution​
bagirrra123 [75]

Answer:

1) Any particle moving in a horizontal plane slowed by friction, deceleration = 32 μ

2) The particle moving by acceleration = P/m - 32μ OR The external force = ma + 32μm

Explanation:

* Lets revise Newton’s Third Law:

- For every action there is a reaction, equal in magnitude and opposite

 in direction.

- Examples:

# 1) A particle moving freely against friction in a horizontal plane

- When no external forces acts on the particle, then its equation of

  motion is;

∵ ∑ forces in direction of motion = mass × acceleration

∵ No external force

∵ The friction force (F) = μR, where μ is coefficient of the frictional force

   and R is the normal reaction of the weight of the particle on the

   surface

∵ The frictional force is in opposite direction of the motion

∴ ∑ forces in the direction of motion = 0 - F

∴ 0 - F = mass × acceleration

- Substitute F by μR

∴ - μR = mass × acceleration

∵ R = mg where m is the mass of the particle and g is the acceleration

  of gravity

∴ - μ(mg) = ma ⇒ a is the acceleration of motion

- By divide both sides by m

∴ - μ(g) = a

∵ The acceleration of gravity ≅ 32 feet/sec²

∴ a = - 32 μ

* Any particle moving in a horizontal plane slowed by friction,

 deceleration = 32 μ

# 2) A particle moving under the action of an external force P in a

  horizontal plane.

- When an external force P acts on the particle, then its equation

 of motion is;

∵ ∑ forces in direction of motion = mass × acceleration

∵ The external force = P

∵ The friction force (F) = μR, where μ is coefficient of the frictional force

   and R is the normal reaction of the weight of the particle on the

   surface

∵ The frictional force is in opposite direction of the motion

∴ ∑ forces in the direction of motion = P - F

∴ P - F = mass × acceleration

- Substitute F by μR

∴ P - μR = mass × acceleration

∵ R = mg where m is the mass of the particle and g is the acceleration

  of gravity

∴ P - μ(mg) = ma ⇒ a is the acceleration of motion

∵ The acceleration of gravity ≅ 32 feet/sec²

∴ P - 32μm = ma ⇒ (1)

- divide both side by m

∴ a = (P - 32μm)/m ⇒ divide the 2 terms in the bracket by m

∴ a = P/m - 32μ

* The particle moving by acceleration = P/m - 32μ

- If you want to fin the external force P use equation (1)

∵ P - 32μm = ma ⇒ add 32μm to both sides

∴ P = ma + 32μm

* The external force = ma + 32μm

7 0
3 years ago
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