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mojhsa [17]
2 years ago
8

Arcsin 0.9331 in degrees​

Physics
1 answer:
lisabon 2012 [21]2 years ago
6 0

Answer:

68.9233231661

Explanation:

Just put it into your calculator, shift sin should do it but it will come up like this: sin^{-1} which is the same as arcsin

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NeX [460]
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5 0
3 years ago
A rock weighs 110 N in air and has a volume of 0.00337 m3 . What is its apparent weight when submerged in water? The acceleratio
pickupchik [31]

Explanation:

It is given that,

Weight of the rock in air, W = 110 N

Since, W = mg

m=\dfrac{W}{g}

m=\dfrac{110\ N}{9.8\ m/s^2}

m = 11.22 kg

We need to find the apparent weight of the rock when it is submerged in water. Apparent weight is equal to the weight of liquid displaced i.e.

M=d\times V

d is the density of water, d=1000\ kg/m^3

V is the volume of rock, V=0.00337\ m^3

M=1000\ kg/m^3\times 0.00337\ m^3

M = 3.37 kg

The apparent weight in water, W = m - M

W=7.85\ kg\times 9.8\ m/s^2

W = 76.93 N

So, the apparent weight of the rock is 76.93 N. Hence, this is the required solution.

4 0
3 years ago
A car slid off an icy 10m bridge and landed 12m away from the bridge. How much time was the car in the air? (Hunt: Projectile)
Contact [7]

You will use the height of the bridge from the ground.

Solution:

Formula to be used is y=Viy(t)+g(t^2)/2

Where:

Vi=initial velocity which is 0 m/s

 y=10 m

Gravitational acceleration or g =9.8m/s^2

T= time you need

Substitute all the given to the formula

10m=(0m/s)(t)+(9.8m/s^2)(t^2)/2

10mx2=9.8m/s^2(t^2)

Now isolate the variable you want to find which is T or time

10mx2/9.8m/s^2=t^2

20m/9.8m/s^2=t^2

Square root of 2.04= square root of t^2

T=1.43 secs

The answer is 1.43 seconds

8 0
3 years ago
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. Define 1 watt power​
iris [78.8K]

Answer:

1 watt power is defined as the 1 Joule of energy consumed per second..

6 0
3 years ago
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What force in Newton is required to accelerate a car starting from rest to 20 m/s in 15 seconds if the mass of the car is 2500 k
Lyrx [107]

We will solve this question using the second law of motion which states that force is directly equal to the product of mass and acceleration.

\sf \: F=ma

Where,

  • F is force
  • m is mass
  • a is acceleration

In our case,

  • F = ?
  • m = 2500 kg
  • a = 20m/s

\tt \: F_{net}  = 2500 \times 20 \\   \tt= 50000

<em>Thus, The force of 50000 Newton is required to accelerate a car of 2500 kg...~</em>

3 0
2 years ago
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