The formula for the quadratic formula is x (c in this case) = (-b(+/-)√(b²-4ac))/2a
This is used for an equation in standard quadratic form: ax² + bx + c = 0
1.) Put it in the correct form, if not already in it.
Ex. c² + 6c + 8 = 0
2.) Identify each part of the equation:
a = 1 (the leading coefficient), b = 6 (the coefficient in front of the second variable), c = 8
3.) Plug in each variable answer
c = (-6(+/-)√(6²-4(1)(8))/2(1)
4.) Simplify
c = (-6(+/-)√(36-(4*8))/2
c = (-6(+/-)√(36-32))/2
c = (-6(+/-)√(4))/2
c = (-6(+/-)2)/2
*Here, the equation splits in two. It becomes:
c = (-6+2)/2 AND c = (-6-2)/2
*Simplify again:
c = -4/2 AND c = -8/2
c = -2 AND c = -4
The answers c = -2 and c = -4 would solve the given equation.
Hope this helps! :)
Answer:
A. 49
Step-by-step explanation:
The average rate of change for the interval ranging from x = 3 to x = 5 for the given function represented in the table above can be calculated using:
x2 = 5
x1 = 3
f(x2) = f(5) = 125
f(x1) = f(3) = 27
Thus,
Average rate of change = 49
Average rate of change of the given table values representing an exponential function is A. 49.
Answer:
3. the answer
Step-by-step explanation:
because I know
Answer:
<em>E. have the same experiences as the treament group, except for</em><em> </em><em>re</em><em>ceiving the treament variable.</em>
