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3 years ago

Please help me I need it.

Mathematics

1 answer:

Inessa05 [86]3 years ago

4 0

G(x) is shifted 7 units below of f(x). if you plug in any number, say 10 as x in f(x), you would get a 100-5=95. in g(x), (10-7)^2 -5= 3^2 -5= 9-5=4. The x would be the same, but the y (f(x) or g(x)) would be shifted down.

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Please help me whit this (if you answer pls show the work)

adell [148]

Answer:

24 ft

Step-by-step explanation:

Use proportions! The old tent has sides of 10ft, and a base of 15ft. The new tent has sides of 16ft and a base of ____ ft.

So, 10/15 = 16/___. Cross multiple and you get 24ft!

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3 years ago

What is the coterminal angle of 330 degrees

aleksandrvk [35]

Positive: 690

Negative: -30

4 0

3 years ago

If she can skip 300 feet in 20 seconds how far could she skip per second

elena55 [62]

300/20 = 15

she can skip 15 feet per second

hope this helps

5 0

2 years ago

Read 2 more answers

Bruce drove 360 miles in 6 hours. If he continues at a consistent speed, how many more hours would he need to drive another 300

Sedaia [141]

Answer:

5 hours

Step-by-step explanation:

If he drove 360 miles in 6 hours, that means he drives 60 miles per hour.

300 divided by 60 is 5, so he will need to drive for 5 more hours

5 0

2 years ago

Read 2 more answers

Suppose that two openings on an appellate court bench are to be filled from current municipal court judges. The municipal court

Ksju [112]

Answer:

$(a)\dfrac{92}{117}$

$(b)\dfrac{8}{39}$

$(c)\dfrac{25}{117}$

Step-by-step explanation:

Number of Men, n(M)=24

Number of Women, n(W)=3

Total Sample, n(S)=24+3=27

Since you cannot appoint the same person twice, the probabilities are <u>without replacement.</u>

(a)Probability that both appointees are men.

$P(MM)=\dfrac{24}{27}X \dfrac{23}{26}=\dfrac{552}{702}\\=\dfrac{92}{117}$

(b)Probability that one man and one woman are appointed.

To find the probability that one man and one woman are appointed, this could happen in two ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.

P(One man and one woman are appointed) $=P(MW)+P(WM)$

$=(\dfrac{24}{27}X \dfrac{3}{26})+(\dfrac{3}{27}X \dfrac{24}{26})\\=\dfrac{72}{702}+\dfrac{72}{702}\\=\dfrac{144}{702}\\=\dfrac{8}{39}$

(c)Probability that at least one woman is appointed.

The probability that at least one woman is appointed can occur in three ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.
Two women are appointed

P(at least one woman is appointed) $=P(MW)+P(WM)+P(WW)$

$P(WW)=\dfrac{3}{27}X \dfrac{2}{26}=\dfrac{6}{702}$

In Part B, $P(MW)+P(WM)=\frac{8}{39}$

Therefore:

$P(MW)+P(WM)+P(WW)=\dfrac{8}{39}+\dfrac{6}{702}\\$P(at least one woman is appointed)=\dfrac{25}{117}$

5 0

3 years ago